Answer:
yes, the student who has 8 pets.
Step-by-step explanation:
the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"
Constants are 4,3. The coefficient is 4.
Answer:
The correct answer is :
1. Line PQ (One line PQ).
Step-by-step explanation:
The first step to solve this question is to draw the plane A with the points P and Q lying on it.
We know that given two different points there is only one line that contains this two different points.
Let's analyze each option.
''2. Lines PQ and QP''
This option is wrong because there aren't two different lines. In fact it is only one line that can be named line PQ or line QP.
''3. The 2 lines PQ and QP plus another line that does not lie in plane A.''
This option is assuming that exist three lines that contain P and Q. This option is also wrong.
''1. Line PQ''
This option is correct. It will be clarify with the drawing I will attach.
''We can't name them all!''
This option is assuming that exist infinite lines that contain P and Q. This option is wrong.
In the drawing I call the line that contains P and Q as line L.
Given that P and Q lie in plane A necessarily the line L must lie on the plane A.
Answer: y = (1 - 0.527)^t
Step-by-step explanation:
y=e^(-0.75t)
y=(e^-0.75)^t
y= 0.47236655^t
1 - 0.47236655 = 0.52763345
y = (1 - 0.527)^t
Answer:
$140
Step-by-step explanation:
Total Amount of chocolate = 100 Pounds
Amount of chocolate in one box = 1 1/4 Pounds = 5/4 Pounds
Number of boxes = 100/(5/4) = 80 boxes
Cost of one box = $1.75
Total selling price = 80×1.75 = 140
The total selling price for all the boxes of chocolate is $140