Answer:
-7a+11
Step-by-step explanation:
Answer:
The average value of 
over the interval ![[-2,5]](https://tex.z-dn.net/?f=%5B-2%2C5%5D)
is 
.
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval ![[-2, 5]](https://tex.z-dn.net/?f=%5B-2%2C%205%5D)
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)
The average value of over the interval is .
The fence you have must fit the perimeter of the rectangle.
With 36 feet of fence, these are the rectangles that you can enclose:
1-ft x 17-ft . . . Area = 17 ft²
2 x 16 . . . Area = 32 ft²
3 x 15 . . . Area = 45 ft²
4 x 14 . . . Area = 56 ft²
5 x 13 . . . Area = 65 ft²
6 x 12 . . . Area = 72 ft²
7 x 11 . . . Area = 77 ft²
8 x 10 . . . Area = 80 ft²
9 x 9 . . . Area = 81 ft²
1/4(6 + 2c) > 3
0.25 (6+ 2c) > 3
1.5 + 0.5c > 3
0.5c > 1.5
c > 3
Or multiply both sides by 4 to get rid of the 1/4,
6 + 2c > 12
2c > 6
c >3
