We don't know WHY there are gravitational forces that attract everything
to everything else.
We DO know that the more mass is involved, the stronger the forces are,
and we know that if an object had no mass then it wouldn't be affected by
gravity. So you could say that it's MASS that gives an object gravity, and
the more mass the object has, the more gravity it has.
The final volume of the gas is 3 L
Explanation:
We can solve this problem by applying Boyle's law, which states that:
"For a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"
Mathematically:
![PV=const.](https://tex.z-dn.net/?f=PV%3Dconst.)
where
P is the pressure of the gas
V is its volume
The equation can also be rewritten as
![P_1 V_1 = P_2 V_2](https://tex.z-dn.net/?f=P_1%20V_1%20%3D%20P_2%20V_2)
For the sample of helium in this problem, we have:
![P_1 = 300 torr](https://tex.z-dn.net/?f=P_1%20%3D%20300%20torr)
![V_1 = 5 L](https://tex.z-dn.net/?f=V_1%20%3D%205%20L)
![P_2 = 500 torr](https://tex.z-dn.net/?f=P_2%20%3D%20500%20torr)
Solving the equation, we can find
, the final volume of the gas:
![V_2 = \frac{P_1 V_1}{P_2}=\frac{(300)(5)}{500}=3 L](https://tex.z-dn.net/?f=V_2%20%3D%20%5Cfrac%7BP_1%20V_1%7D%7BP_2%7D%3D%5Cfrac%7B%28300%29%285%29%7D%7B500%7D%3D3%20L)
Learn more about ideal gases:
brainly.com/question/9321544
brainly.com/question/7316997
brainly.com/question/3658563
#LearnwithBrainly
Answer:
The height of the water above the hole in the tank is 58 mm
Explanation:
In order to solve this problem we need to draw a sketch of the dimensions that include the input variables of the problem.
Where:
x = 0.579[m]
y = 1.45 [m]
Using the following kinematic equation we can find the time that takes the water to hit the ground, and then with this time, we can find the velocity of the water in the x-component.
![y = y_{o} +v_{o} *t+\frac{1}{2} *g*t^{2} \\](https://tex.z-dn.net/?f=y%20%3D%20y_%7Bo%7D%20%2Bv_%7Bo%7D%20%2At%2B%5Cfrac%7B1%7D%7B2%7D%20%2Ag%2At%5E%7B2%7D%20%5C%5C)
It is necessary to clarify the value of each of the respective variables below
y = - 1.45 [m] "It is negative because this point is below the water outlet"
yo = 0
vo = 0 "The velocity is zero because the component of the speed on the Y-axis does not exist"
therefore:
![-1.45=0.5*(-9.81)*t^{2} \\t = \sqrt{\frac{1.45}{0.5*9.81} } \\t = 0.543[s]](https://tex.z-dn.net/?f=-1.45%3D0.5%2A%28-9.81%29%2At%5E%7B2%7D%20%5C%5Ct%20%3D%20%5Csqrt%7B%5Cfrac%7B1.45%7D%7B0.5%2A9.81%7D%20%7D%20%5C%5Ct%20%3D%200.543%5Bs%5D)
The next step is to determine the velocity in component x, knowing the time.
![v=\frac{x}{t} \\v=\frac{0.579}{.543} \\v = 1.06[m/s]](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bx%7D%7Bt%7D%20%5C%5Cv%3D%5Cfrac%7B0.579%7D%7B.543%7D%20%5C%5Cv%20%3D%201.06%5Bm%2Fs%5D)
Now using torricelli's law we can find the elevation.
![v=\sqrt{2*g*h} \\h=\frac{v^{2} }{2*g} \\h=\frac{1.06^{2} }{2*9.81} \\h= 0.057[m] = 57.95[mm]](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2%2Ag%2Ah%7D%20%5C%5Ch%3D%5Cfrac%7Bv%5E%7B2%7D%20%7D%7B2%2Ag%7D%20%5C%5Ch%3D%5Cfrac%7B1.06%5E%7B2%7D%20%7D%7B2%2A9.81%7D%20%5C%5Ch%3D%200.057%5Bm%5D%20%3D%2057.95%5Bmm%5D)
H = height of the pole = ?
BC = ED = height of the transit = 4 ft
CD = BE = distance moved away from the base of the pole = 140 ft
Consider the ΔABE
tan44 = AE/BE
tan44 = h/140
h = 140 tan44
h = 135.2 ft
H = height of pole = AE + ED = h + ED = 135.2 + 4
H = 139.2 ft
Answer:
2.5 km/30min
Explanation:
Divide 5 by 2 because 30 min is half of 1 hour. when you do that you get 2.5