Question

A school bus is moving 26.8 m/s on

Answer 1

The time taken for the bus to travel 95.1 m is 2.8 s

How to determine the final velocity

• Initial velocity (u) = 26.8 m/s
• Acceleration (a) = 4.73 m/s²
• distance (s) = 95.1 m
• Final velocity (v) = ?

v² = u² + 2as

v² = 26.8² + (2 × 4.73 × 95.1)

v² = 1617.886

Take the square root of both sides

v² = √1617.886

v = 40.2 m/s

How to determine the time

• Initial velocity (u) = 26.8 m/s
• Acceleration (a) = 4.73 m/s²
• Final velocity (v) = 40.2 m/s
• Time (t) = ?

v = u + at

40.2 = 26.8 + (4.73 × t)

Collect like terms

4.73 × t = 40.2 - 26.8

4.73 × t = 13.4

Divide both side by 4.73

t = 13.4 / 4.73

t = 2.8 s

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