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Liula [17]
2 years ago
11

A school bus is moving 26.8 m/s on

Physics
1 answer:
Elodia [21]2 years ago
3 0

The time taken for the bus to travel 95.1 m is 2.8 s

<h3>How to determine the final velocity</h3>
  • Initial velocity (u) = 26.8 m/s
  • Acceleration (a) = 4.73 m/s²
  • distance (s) = 95.1 m
  • Final velocity (v) = ?

v² = u² + 2as

v² = 26.8² + (2 × 4.73 × 95.1)

v² = 1617.886

Take the square root of both sides

v² = √1617.886

v = 40.2 m/s

<h3>How to determine the time</h3>
  • Initial velocity (u) = 26.8 m/s
  • Acceleration (a) = 4.73 m/s²
  • Final velocity (v) = 40.2 m/s
  • Time (t) = ?

v = u + at

40.2 = 26.8 + (4.73 × t)

Collect like terms

4.73 × t = 40.2 - 26.8

4.73 × t = 13.4

Divide both side by 4.73

t = 13.4 / 4.73

t = 2.8 s

Learn more about velocity:

brainly.com/question/3411682

#SPJ1

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The argon molecules become solid when the temperature decrease from 20C to -190 C.

<h3>What changes occur in argon?</h3>

The changes in arrangement and movement of the particles of the argon occurs as the temperature of the air decreased because the argon gas begins to freeze. The freezing point of argon is -189 Celsius so when the temperature decrease from 20C to -190 C, the argon molecules becomes solid.

So we can conclude that the argon molecules become solid when the temperature decrease from 20C to -190 C.

Learn more about argon here: brainly.com/question/23949935

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I’m done with Brainly so I’m giving out my points #5
pshichka [43]

Answer:

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Explanation:

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Where the sun's energy is produced
stellarik [79]
Well,

The sun's energy is produced mainly in the core, which has sufficient temperature to initiate nuclear fusion.

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Earth's orbit around the Sun is slightly elliptical. Thus, Earth actually gets closer to the Sun during part of the year. What h
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Answer:

C)Earth's orbital speed is greater when it is closer to the Sun than when it is farther from the Sun.

Explanation:

We can use Kepler's 2nd law or the law of area to answer this question.

The law states that the rate of area swept out by a planet's orbit is same throughout the orbit. For the farthest point since the distance is large as compared to to the nearest point, the possibility that area swept is large. Hence, to compensate the extra swept area. the orbital speed has to decrease  at the largest point.

Hence, planet's speed is greater when it is closer to sun than the speed when it is farther.

6 0
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On a bet, you try to remove water from a glass by blowing across the top of a vertical straw immersed in the water. What is the
MArishka [77]

Answer:

       v₂ = 0.56 m / s

Explanation:

This exercise can be done using Bernoulli's equation

        P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

Where points 1 and 2 are on the surface of the glass and the top of the straw

The pressure at the two points is the same because they are open to the atmosphere, if we assume that the surface of the vessel is much sea that the area of ​​the straw the velocity of the surface of the vessel is almost zero v₁ = 0

The difference in height between the level of the glass and the straw is constant and equal to 1.6 cm = 1.6 10⁻² m

We substitute in the equation

         P_{atm} + ρ g y₁ = P_{atm} + ½ ρ v₂² + ρ g y₂

         ½ v₂² = g (y₂-y₁)

        v₂ = √ 2 g (y₂-y₁)

Let's calculate

        v₂ = √ (2 9.8 1.6 10⁻²)

       v₂ = 0.56 m / s

5 0
3 years ago
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