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lesya692 [45]
3 years ago
5

During the construction of an office building, a hammer is accidentally dropped from a height of 784 ft. the distance (in feet)

the hammer falls in t sec is s = 16t2. what is the hammer's velocity when it strikes the ground?
Physics
2 answers:
Serga [27]3 years ago
7 0
T= 24.5 feet per second. That is the velocity it reaches at the end of its fall
Sergio [31]3 years ago
4 0

Answer:

The hammer's velocity when it strikes the ground is 128 ft/s.

Explanation:

Given that,

The distance (in feet) the hammer falls in t sec is given by the relation as :

s=16t^2

The hammer is accidentally dropped from a height of 784 ft. We need to find the hammer's velocity when it strikes the ground. We know that the velocity of an object is equal to :

v=\dfrac{ds}{dt}\\\\v=\dfrac{d(16t^2)}{dt}\\\\v=32t

When the hammer strikes ground, s = 256 ft

So,

16t^2=256\\\\t^2=16\\\\t=4\ s

So, the velocity of the hammer when it strikes the ground is given by :

v=32t=32\times 4\\\\v=128\ ft/s

So, the hammer's velocity when it strikes the ground is 128 ft/s. Hence, this is the required solution.

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