The two coins chosen have to be a quarter and a penny. That leaves you with three pennies. You originally had 14 coins. You took out two you now have 12.
<span>3/12 = 1/4 </span>
2 ways
zero product property
easy way
zero product
factor perfect square
m^2-3^2=0
(m-3)(m+3)=0
set each to zero
m-3=0
x=3
m+3=0
m=-3
m=-3 or 3
easy way
add 9 to both sides
m^2=9
sqrt both sides remember to take postive and negative roots
m=+/-3
m=-3 or 3
B is answer
6x+1 / 2x +6 - 5/2
Factor 2 out of the denominator of the first fraction:
6x+1 / 2(x+3) - 5/2
Rewrite 5/2 to have a common denominator with the first fraction:
6x+1/2(x+3) - 5(x+3) / 2(x+3)
Simplify terms:
6x +1 - 5(x+3) / 2(x+3)
Use distributive property:
6x +1 - 5x -15 / 2(x+3)
Combine like terms for final answer:
(x-14) / 2(x+3)
Sorry idk, but I’ll try to do it
Assuming m<PTQ is a right angle (measuring 90°) and angle TQP is already marked as 63° while knowing there are 180° in a triangle, you would take 180°- 63°- 90°= 27
