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3 years ago

9

A force of 125N lifts a 10.0kg mass while gravity pulls down with a force of 100.0N. How long will it take for the mass to move

2.00 meters from rest

1 answer:

Sindrei [870]3 years ago

4 0

Explanation:

Hope this example helps you

Mark my example as brainalist

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A motorcycle being driven on a dirt path hits a

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Impulse = mass * change in velocity (change in momentum) = Force * change in time

So, F=(m*change in v)/(change in t)
F=(60*20)/0.5=2400N

Therefore the magnitude of the average force exerted on the cyclist by the haystack is 2.4*10^3N

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4 years ago

The universe is mostly made up of what?

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D. Empty Space

Imagine an apple in the center of a football field. Pretend like that apple is the nucleus of an atom. The electrons would be at the end-zones. The universe is just a butttonne of empty space

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4 years ago

Two blocks with masses 1 and 2 are connected by a massless string that passes over a massless pulley as shown. 1 has a mass of 2

Bess [88]

Answer:

The acceleration of $M_2$ is $a = 0.7156 m/s^2$

Explanation:

From the question we are told that

The mass of first block is $M_1 = 2.25 \ kg$

The angle of inclination of first block is $\theta _1 = 43.5^o$

The coefficient of kinetic friction of the first block is $\mu_1 = 0.205$

The mass of the second block is $M_2 = 5.45 \ kg$

The angle of inclination of the second block is $\theta _2 = 32.5^o$

The coefficient of kinetic friction of the second block is $\mu _2 = 0.105$

The acceleration of $M_1 \ and\ M_2$ are same

The force acting on the mass $M_1$ is mathematically represented as

$F_1 = T - M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1$

=> $M_1 a = T - M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1$

Where T is the tension on the rope

The force acting on the mass $M_2$ is mathematically represented as

$F_2 = M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

$M_2 a = M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

At equilibrium

$F_1 = F_2$

So

$T - M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1 =M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

making a the subject of the formula

$a = \frac{M_2 g sin \theta_2 - M_1 g sin \theta_1 - \mu_1 M_1g cos \theta - \mu_2 M_2 g cos \theta_2 }{M_1 +M_2}$

substituting values $a = \frac{(5.45) (9.8) sin (32.5) - (2.25) (9.8) sin (43.5) - (0.205)*(2.25) *9.8cos (43.5) - (0.105)*(5.45) *(9.8) cos(32.5) }{2.25 +5.45}$

=> $a = 0.7156 m/s^2$

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4 years ago

What is potential energy??

Murrr4er [49]

Answer:

the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.

hope this helps

have a good day :)

Explanation:

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3 years ago

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An archer pulls back the string of a bow to release an arrow at a target. Which kind of potential energy is transformed to cause

Morgarella [4.7K]

It is elastic energy

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4 years ago

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