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3 years ago

you are sitting behind the bus driver on a moving bus in relation to a person standing on the sidewalk you are what

Physics

1 answer:

grigory [225]3 years ago

4 0

You are sitting behind the bus driver on a moving bus in relation to a person standing on the sidewalk you are what

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relative to sidewalk you are moving with the driver

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Emily is a competitive swimmer. Why does wearing a swim cap help Emily swim faster?

sladkih [1.3K]

Answer:

It's helps Emily became when she swims her hair is not in the way creating friction and making her swim faster. friction acts between two metals blocks that slide past each other.

Explanation:

6 0

3 years ago

I need help with this someone help me?

Brilliant_brown [7]

Graph A so answer B also why isn’t answer a with graph A and B with graph B etc like that’s just confusing lol

3 0

3 years ago

A rock is dropped from the edge of a cliff into a pool of water. Assume free-fall acceleration is 10 m/s per second, and air res

il63 [147K]

Answer:

20 m

Explanation:

From the equation of motion,

S = ut+1/2gt²................................. Equation 1

Where S = Height, u = initial velocity, t = time, g = acceleration due to gravity.

Note: Because the rocked is being dropped from a height, acceleration due to gravity is positive (g), and initial velocity (u) is negative

Given: t = 2.0 s, g = 10 m/s², u = 0 m/s (dropped from height)

Substituting into equation 1

S = 0(2) + 1/2(10)(2)²

S = 5(4)

S = 20 m

Hence the height of the the cliff above the pool is 20 m

7 0

3 years ago

A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-

Alisiya [41]

First we need to convert the angular speed from rpm to rad/s. Keeping in mind that
$1 rev= 2 \pi rad$
$1 min = 60 s$
the angular speed is
$\omega = 7.18 \frac{rev}{min} \cdot \frac{2 \pi}{60} = 0.75 rad/s$

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
$v= \omega r = (0.75 rad/s)(4.65 m)=3.50 m/s$

3 0

3 years ago

What temperature does nuclear fusion begin?

pishuonlain [190]

Answer:

15,000,000 degrees Celsius

Explanation:

After the temperature reaches this degree, nuclear fusion begins to start.

5 0

3 years ago

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