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Bond [772]
4 years ago
10

A container of gas is at a pressure of 3.7 x 105 pa. how much work is done by the gas if its volume expands by 1.6 m3? show your

work.
Physics
2 answers:
dem82 [27]4 years ago
7 0
<span>W = P(deltaV)
W = (3.7 X 10^5)(1.6) = 5.92 X 10^5 Joules </span>
melomori [17]4 years ago
7 0

Answer:

5.92x10^5 J

Explanation:

In order to solve this, you need to know the expression or formula to use. In this case:

W = P * ΔV

Where:

P = pressure

V = change in volume.

Now, this is actually easy, and we need to put the values given in the exercise in the above expression and solve for W. Remember that 1 Pa is 1 kg/ m.s²

W = 3.7x10^5 kg / m.s² * 1.6m³

W = 592,000 kg/ m².s²

And 1 kg / m².s² = 1 J so

W = 592,000 J or simply 5.92x10^5 J or even 592 kJ

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If you are 5.00ft and 10.0in tall, what is your height in meters
Stolb23 [73]

The answer that I got was 5'8333..., which is the total for height and in inches, all of this would be 70 inches, or 1.78 meters, or 178 centimeters, or 1780 millimeters, but just go for the height that person is going to be at, 5'833... (this is repeated so just round it up to 5'8 if you want to.)

Hope this helped!

Nate

8 0
3 years ago
What are some other examples of scientific knowledge that must have resulted from indirect evidence?
n200080 [17]

Answer:

The atomic model, the structure of the solar system, and the theory of black holes are examples of models created using indirect evidence.

Explanation:

I have no explanation sorry.

5 0
3 years ago
Arsenic diffusion in Si: Arsenic is diffused into a thick slice of silicon with no previous arsenic in it at 1100ºC. If the surf
Rainbow [258]

Answer:

Diffusion time is 7.42 h

Solution:

As per the question:

Temperature, T = 1100^{\circ}C

Surface concentration of arsenic, C_{S} = 5.0\times 10^{18}\ atoms/cm^{3}

Surface concentration below Silicon surface, C_{x} = 1.5\times 10^{16}\ atoms/cm^{3}

D = 3.0\times 10^{- 14}\ cm^{2}/s

x = 1.2\mu m = 1.2\times 10^{- 4}\ cm

Initial concentration at t = 0, C_{o} = 0

Now, by using Flick's second eqn:

\frac{C_{S} - C_{x}}{C_{x} - C_{o}} = erf(\frac{x}{\sqrt{Dt}})

Thus by putting appropriate values:

\frac{5.0\times 10^{18} - 1.5\times 10^{16}}{5.0\times 10^{18}} = erf(\frac{1.2\times 10^{- 4}}{2\sqrt{3.0\times 10^{- 14}t}})

0.997 = erf(\frac{364.4}{\sqrt{t}})              (1)

Now,

erf(z) = 0.997

Now, from error function values tabulation:

For z = 2.0, erf(z) = 0.998

For z = 2.2, erf(z) = 0.995

Now,

With the help of linear interpolation method:

\frac{z - 2}{2.2 - 2.0} = \frac{0.997 - 0.995}{0.998 - 0.995}

z = 2.12

Now, using eqn (1) and above value:

\frac{364.4}{\sqrt{t}} = 2.12

t = (\frac{364.4}{2.12})^{2} = 26700 s

t = \frac{26700}{3600} = 7.42\ h

7 0
3 years ago
What is 4 differences between saturated unsaturated and supersaturated solutions
Dennis_Churaev [7]

Answer:

Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible.

3 0
3 years ago
A rotating water pump works by taking water in at one side of a rotating wheel, and expelling it from the other side. If a pump
Xelga [282]

Answer:

Explanation:

initial angular velocity, ωo = 0 rad/s

angular acceleration, α = 30.5 rad/s²

time, t = 9 s

radius, r = 0.120 m

let the velocity is v after time 9 s.

Use first equation of motion for rotational motion

ω = ωo + αt

ω = 0 + 30.5 x 9

ω = 274.5 rad/s

v = rω

v = 0.120 x 274.5

v = 32.94 m/s

8 0
3 years ago
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