Question

A container of gas is at a pressure of 3.7 x 105 pa. how much work is done by the gas if its volume expands by 1.6 m3? show your work.

Answer 1

W = P(deltaV)
W = (3.7 X 10^5)(1.6) = 5.92 X 10^5 Joules 

Answer 2

Answer:

5.92x10^5 J

Explanation:

In order to solve this, you need to know the expression or formula to use. In this case:

W = P * ΔV

Where:

P = pressure

V = change in volume.

Now, this is actually easy, and we need to put the values given in the exercise in the above expression and solve for W. Remember that 1 Pa is 1 kg/ m.s²

W = 3.7x10^5 kg / m.s² * 1.6m³

W = 592,000 kg/ m².s²

And 1 kg / m².s² = 1 J so

W = 592,000 J or simply 5.92x10^5 J or even 592 kJ