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MariettaO [177]
4 years ago
13

An archer pulls back the string of a bow to release an arrow at a target. Which kind of potential energy is transformed to cause

the motion of the arrow?
Physics
2 answers:
Morgarella [4.7K]4 years ago
8 0
It is elastic energy
lora16 [44]4 years ago
6 0
I think the kind of potential energy that is transformed to cause the motion of the arrow would be elastic energy. Elastic energy<span> is the potential mechanical </span>energy <span>stored in the configuration of a material or physical system as work is performed to distort its volume or shape. 

Thank you for posting your question here at brainliest!
I hope my question helps you!</span>
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How do you find average velocity (average) from acceleration) and time (t)?
Tasya [4]

Average velocity is defined as the ratio in change in position to change in time,

v[ave] = ∆x/∆t

which on its own doesn't have anything to do with acceleration.

<u>If acceleration is constant</u>, the average velocity is the literal average of the initial and final velocities,

v[ave] = (v[final] + v[initial]) / 2

If this constant acceleration has magnitude a, the final velocity can be expressed in terms of the initial velocity by

v[final] = v[initial] + a*t

and plugging this into the previous equation gives

v[ave] = (v[initial] + a*t + v[initial])/2

v[ave] = v[initial] + 1/2*a*t

If the body in consideration is <u>initially at rest</u>, then

v[ave] = 1/2*a*t

which might be the relation you're looking for. But bear in mind the conditions I've underlined.

<u>If acceleration is not constant and changes over time</u>, so that the acceleration is some function of time a(t), then you can determine the velocity function v(t) by using the fundamental theorem of calculus. You need to know a particular velocity for some time to completely characterize v(t), though. For example, if you're given the initial velocity v[initial] = v(0), then

\displaystyle v(t) = v(0) + \int_0^t a(u) \, du

or if you know any other velocity for some time t₀ > 0,

\displaystyle v(t) = v(t_0) + \int_{t_0}^t a(u) \, du

8 0
3 years ago
Which of the following metals reacts with oxygen and acids but is not very reactive with water?
Lina20 [59]

Calcium is reactive with oxygen, acid, and water. Copper is not reactive with water as well as with acids, whereas magnesium is reactive with acid but reactive with water.

<h3>What is a Chemical Reaction?</h3>

One or more chemicals (the reactants) are changed into one or more other compounds during a chemical reaction (the products).Substances are made up of chemical components or chemical elements.

Each calcium atom donates a pair of electrons to an oxygen atom during the interaction between calcium and oxygen to create calcium oxide.

When calcium reacts with hydrochloric acid, it releases bubbles of hydrogen gas, and when large chunks of calcium react with hydrochloric acid, it releases hydrogen gas. Calcium in reaction with water produces calcium hydroxide and hydrogen gas

When magnesium and oxygen interact, they produce light that is so strong that it temporarily impairs your vision. Magnesium burns so brilliantly because it produces a lot of heat while doing so.

Magnesium reacts with hot water or water vapor to produce hydrogen gas and magnesium hydroxide.

Acid does not react with copper. Metals such as lead, copper, silver, and gold do not react with water at all.

To get more info about the chemical reaction:

brainly.com/question/3461108

#SPJ1

7 0
2 years ago
Tidal Forces near a Black Hole. An astronaut inside a spacecraft, which protects her from harmful radiation, is orbiting a black
arlik [135]

Answer:

833.4801043*10^6N on ear that is closer to Black hole.

13.83803929*10^6N On ear that is farther from Black hole.

Explanation:

This problem can be solved as two masses that are at two different location from a bigger mass whose gravity affects both.

tension is an equal and opposite force that is exerted in response to applied force.

so on ear that is closer to black hole would have tension that is equal in magnitude and opposite in direction to gravitational force that ear experience due to the black hole at that location.

this true for ear that is further away from black hole as well.

(1) Force on ear that is closer to black hole.

                                                 F =\frac{m_{1}*m_{2}  }{r^2} G

                    m_{1}= 5*1.989*10^30kg is mass of Black hole.

                     m_{2}= 0.030kg is mass of ear that is close to black hole.

                    G = 6.679*10^-11m^3*kg^-1*s^-2

                     r = 120km-\frac{6}{100000} km=119.99994km=119999.94m

Note, we have subtracted because ear is closer to black hole.

plugging all this in formula gives.

                                      F = 833.4801043*10^6N

       That is tension of ear.

(2) Force on ear that is further from black hole.

                              F =\frac{m_{1}*m_{2}  }{r^2} G

                    m_{1}= 5*1.989*10^30kg is mass of Black hole.

                     m_{2}= 0.030kg is mass of ear that is close to black hole.

                    G = 6.679*10^-11m^3*kg^-1*s^-2

         this time r is further away from black hole so it would be.

                       r = 120km+\frac{6}{100000} km = 120000.06m

Plugging this all in we get

                          F = 13.83803929N

and that is tension on ear that is further from black hole.

Notice the tension difference, and order of magnitude of tension,it is enormous .

this astronaut is lethally close to black hole.

5 0
3 years ago
It takes five hours to drive from Fort Worth to Midland, which is a distance of 300 miles. What
Shkiper50 [21]

Answer:

60

Explanation:

(hint: speed = distance/time)

8 0
3 years ago
A potter’s wheel moves from rest to an angular speed of 0.20 rev/s in 23.8 s. Assuming constant angular acceleration, what is it
ser-zykov [4K]

Answer:

0.053 rad/s^2

Explanation:

0.2 rev/s = 0.2 rev/s * 2π rad/rev = 0.4π rad/s

Since the angular acceleration is assumed to be constant, and the wheel's angular speed is increasing from rest (0 rad/s) to 0.4π rad/s within 23.8s. Then the angular acceleration must be

\alpha = \Delta \omega / \Delta t = \frac{0.4 \pi - 0}{23.8} = 0.053 rad/s^2

8 0
3 years ago
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