Answer: In this case, you can estimate that the solubility of potassium nitrate in water at
60
∘
C
is equal to about
solubility
≈
110 g / 100 mL water
−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
This tells you that a saturated solution of potassium nitrate will hold about
110 g
of dissolved salt, i.e. of dissociated salt, per
100 mL
of water at
60
∘
C
.
Answer:
. The authorities have closed the casino.(change in passive)
Answer:
The ration of the molar solubility is 165068.49.
Explanation:
The solubility reaction of the magnesium hydroxide in the pure water is as follows.
![[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Initial 0 0
Equili +S +2S
Final S 2S
![K_{sp}=[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Solubility of 
in 0.180 M NaOH is a follows.
Initial 0 0
Equili +S +2S
Final S 2S+0.180M
Therefore, The ration of the molar solubility is 165068.49.
Answer:
C,
to make it simple 10 to the power of 3 is 1000, and 1000 multiplied by 3.753 is equal to 3,753.
<span>Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles. We calculate as follows:
</span>5.31×10^21 platinum atoms ( 1 mol / 6.022 x 10^23 atoms ) ( 78 grams / 1 mol ) = 0.6878 grams platinum
