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3 years ago

Consider the balanced equation below

Chemistry

2 answers:

dybincka [34]3 years ago

6 0

The mole ratio of PCl3 to PCl5 is 1:1

<u><em> Explanation</em></u>

PCl3 + Cl2→ PCl5

Mole ratio - Is the ratio between amount of mole of two compound.

The mole ratio is determined by considering the coefficient in front of the formula in a balanced chemical equation.

The coefficient in front of PCl3 in equation above is 1 , while the coefficient in front of PCl5 is 1, therefore the mole ratio is 1:1

Svet_ta [14]3 years ago

3 0

PCl₃ + Cl₂ = PCl₅

1:1

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Solution 1 consists of 80% benzene and 20% toluene. Solution 2 consists of 30% benzene and 70% toluene. a) How many mL of Soluti

Olenka [21]

Answer:

Answer a) is 2000 mL solution 1.

Answer b) is 40 mL solution 1 and 60 mL solution 2.

Answer c) isn't possible to produce a solution with 90% benzene and 10% toluene because is a percentage of benzene higher than the solution 1 and solution 2.

Explanation:

You can solve using an equation system base on the benzene percentage/ratio of each solution.

Answer a) X-> mL of solution 1

x*0.8+500*0.3=(500+ x)*0.7

x *0.8+500*0.3=500*0.7+ x*0.7

x*(0.8-0.7)=500*(0.7-0.3)

X*0.1=200

x=2000mL

Answer b) X-> mL of solution 1

x*0.8+(100-x)*0.3=(100)*0.5

x *0.8+100*0.3-x*0.3=50

x*(0.8-0.3)=50-30

x*(0.5)=20

x=40 mL

mL of solution 2=(100-x)=100-40=60 mL

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3 years ago

What is the main material for b horizon

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3 years ago

The titration of 25.0 mL of an iron(II) solution required 18.0 mL of a 0.145 M solution of dichromate to reach the equivalence p

Svetlanka [38]

Answer:

0.64 M

Explanation:

Given:

Volume of iron(II) solution (V₁) = 25.0 mL = 0.025 L

Molarity of iron(II) solution (M₁) = ?

Number of moles of iron(II) solution (n₁) = ?

Volume of dichromate solution (V₂) = 18.0 mL = 0.018 L

Molarity of dichromate solution (M₂) = 0.145 M

Number of moles of dichromate solution (n₂) = ?

Molarity is equal to the ratio of moles and volume.

So, molarity of dichromate solution is given as:

$M_2=\frac{n_2}{V_2}\\\\n_2=M_2\times V_2=0.145\times 0.018 = 2.61\times 10^{-3}\ mol$

Now, let us write the complete balanced reaction for the given situation.

So, the complete balanced equation is given below.

$6Fe^{2+}(aq)+Cr_2O_7^{2-}(aq)+14H^+(aq)\to 6Fe^{3+}(aq)+2Cr^{3+}(aq)+7H_2O$

From the equation, it is clear that, 1 mole of dichromate is required for 6 moles of iron(II) solution.

So, using unitary method, we find the number of moles of iron(II) solution.

1 mole of dichromate = 6 moles of iron(II)

∴ n₂ moles of dichromate = 6n₂ moles of iron(II)

= $6\times 2.61\times 10^{-3}=0.016\ mol\ Fe^{2+}$

So, 0.016 moles of iron(II) is needed. Therefore, $n_1=0.016\ mol$

Now, molarity of iron(II) solution is given as:

Molarity = Moles ÷ Volume

$M_1=\frac{n_1}{V_1}\\\\M_1=\frac{0.016\ mol}{0.025\ L}=0.64\ M$

Therefore, the molarity of the iron(II) solution is 0.64 M.

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What is the role of neutrons in an atom??

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The hydrogen moles and the oxygen between each other are that the oxygen had 88.8 grams and hydrogen has 11.19

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