Answer: we embrace and are simultaneously respecting their rational autonomy
Explanation:
Ursula is a student of Kantian philosophy who argues that we should never use people as a means to an end unless we embrace and are simultaneously respecting their rational autonomy
Answer:
La fuerza eléctrica es -8.2*10⁻⁸ N
Explanation:
El enunciado correcto es: <em>¿Cuál es la fuerza eléctrica sobre el electrón (-1.6 x 10⁻¹⁹c) de un átomo de hidrógeno ejercida por el protón (1.6 x 10⁻¹⁹c)? Supóngase que la distancia entre el electrón y el protón es de 5.3 x 10⁻¹¹ m</em>
Entre dos o más cargas aparece una fuerza denominada fuerza eléctrica. Su valor depende del valor de las cargas y de la distancia que las separa, mientras que su signo depende del signo de cada carga. Las cargas del mismo signo se repelen entre sí, mientras que las de distinto signo se atraen.
La fuerza eléctrica con la que se atraen o repelen dos cargas puntuales en reposo es directamente proporcional al producto de las mismas e inversamente proporcional al cuadrado de la distancia que las separa:

donde:
-
F es la fuerza eléctrica de atracción o repulsión. En el Sistema Internacional (S.I.) se mide en Newtons (N).
- q1 y q2 son lo valores de las dos cargas puntuales. En el S.I. se miden en Culombios (C).
- d es el valor de la distancia que las separa. En el S.I. se mide en metros (m).
- K es una constante de proporcionalidad llamada constante de la ley de Coulomb. Depende del medio en el que se encuentren las cargas. Para el vacío K tiene un valor aproximadamente de 9*10⁹
.
En este caso:
- K= 9*10⁹

Reemplazando:

Resolviendo:
F= -8.2*10⁻⁸ N
<u><em>La fuerza eléctrica es -8.2*10⁻⁸ N</em></u>
<h2>
Answer: 1000 J</h2>
The Work
done by a Force
refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.
It should be noted that it is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:
Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:
(1)
When they are not parallel, both directions form an angle, let's call it
. In that case the expression to calculate the Work is:
(2)
For example, in order to push the 200 N box across the floor, you have to apply a force along the distance
to overcome the resistance of the weight of the box (its 200 N).
In this case both <u>(the force and the distance in the path) are parallel</u>, so the work
performed is the product of the force exerted to push the box
by the distance traveled
. as shown in equation (1).
Hence:
>>>>This is the work
Answer:
4) Driving in a straight line at 60 miles per hour
Explanation:
1) Driving 60 miles per hour around a curve
2) Going from 0 to 60 miles per hour in 10 seconds
3) Slamming on the brakes to come to a stop at a stop sign
4) Driving in a straight line at 60 miles per hour
1) The speed is constant here, but in circular motion you have an acceleration that is v^2/r, where v is the speed and r the radius
2) You are accelerating from 0 to 60
3) You are desaccelerating
4) constant speed , no acceleration