Answer:
15√2 N
Explanation:
The acceleration is given by ...
a = F/m = 5t/5 = t . . . . meters/second^2
The velocity is the integral of acceleration:
v = ∫a·dt = (1/2)t^2
This will be 9 m/s when ...
9 = (1/2)t^2
t = √18 . . . . seconds
And the force at that time is ...
F = 5(√18) = 15√2 . . . . newtons
Answer:
Refractive index, n = 2.419
Explanation:
It is given that,
Speed of light in the medium,
Speed of light in the vacuum,
Let n is the index of refraction for a medium. We know that the refractive index for any medium is equal to the ratio of speed of light in vacuum to the speed of light in medium. It can be written as :
n = 2.419
So, the index of refraction for a medium is 2.419. Hence, this is the required solution.
Answer:
161376 kJ
Explanation:
The equation for standard Gibbs energy free energy for a reaction is -
ΔG⁰ = ΔH⁰ - TΔS⁰
The values of ΔH⁰, T and ΔS⁰ are given in the question as
ΔH⁰ = -2256 kJ
T = 298 K
ΔS⁰ = -549.1 kJ
So, putting these values in the above equation we get
ΔG⁰ = -2256 - (-549.1 × 298)
ΔG⁰ = -2256 + 163631.8 = 161375.8 ≈ 161376 kJ
Thus, the standard Gibbs free energy for the reaction mentioned in the question will be 161376 kJ.