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Anon25 [30]
3 years ago
7

Calculate the index of refraction for a medium in which the speed of light is 1.239 ✕ 108 m/s. (The speed of light in vacuum is

2.998 ✕ 108 m/s. Enter your answer to at least three decimal places.)
Physics
1 answer:
True [87]3 years ago
3 0

Answer:

Refractive index, n = 2.419

Explanation:

It is given that,

Speed of light in the medium, v=1.239\times 10^8\ m/s

Speed of light in the vacuum, c=2.998\times 10^8\ m/s

Let n is the index of refraction for a medium. We know that the refractive index for any medium is equal to the ratio of speed of light in vacuum to the speed of light in medium. It can be written as :

n=\dfrac{c}{v}

n=\dfrac{2.998\times 10^8\ m/s}{1.239\times 10^8\ m/s}

n = 2.419

So, the index of refraction for a medium is 2.419. Hence, this is the required solution.

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A student blows in a tube with one closed in that is 0.49 m long. If the frequency of the sound is 358 Hz what is the speed wave
BaLLatris [955]

Answer:175.42m/s

Explanation:

Wavelength=0.49m

Frequency=358Hz

Velocity=frequency x wavelength

Velocity=358x0.49

Velocity=175.42m/s

6 0
3 years ago
Star a has an absolute magnitude of 8. what is its apparent magnitude at a distance of 100 pc
tresset_1 [31]
From the definition of apparent magnitude, we know that:
m_{1} - m_{2} = -2.5Log( \frac{F_{1}}{F_{2}} )
where:
m = apparent magnitude
F = corresponding flux

We also know that the flux is given by the formula:
F =  \frac{L}{4 \pi  d^{2} }
where:
L = luminosity
d = distance

Therefore:
\frac{F_{1} }{F_{2}} = (\frac{L_{1} }{4 \pi d_{1}^{2} })(\frac{4 \pi d_{2}^{2} }{L_{2} }) \\ =  \frac{L_{1}d_{2}^{2}}{L_{2}d_{1}^{2}}

Now, let's apply these formulae to the same star (therefore, same luminosity), using apparent magnitude and absolute magnitude (which is defined as the apparent magnitude the star would have if it were at a distance of 10pc):
m - M = 2.5 Log ( \frac{d}{10pc})^{2}

Now, let's solve for m:
m = M + 2.5 Log ( \frac{d}{10})^{2}
= <span>8 + 2.5 Log ( \frac{100}{10})^{2}</span>
= 13

Hence, the apparent magnitude of the star would be m = +13
3 0
3 years ago
A circus performer walked up and to the right for a total displacement of 10\,\text m10m10, start text, m, end text along a diag
Tanya [424]

Answer: 5m

(10m) sin 30

=5m

8 0
3 years ago
An underwater diver sees the sun 57 ∘ above horizontal. how high is the sun above the horizon to a fisherman in a boat above the
nydimaria [60]

Angle at which under water diver sees the sun from horizontal = 57^{0}

Angle from normal direction =  90 - 57 = 33^{0}

Refractive index of water = 1.33

Refractive index of water = 1

We have the equation

   1.33 * sin 33^{0}= 1 *sin \alpha

 \alpha = sin ^{-1} (\frac{1.33sin33}{1} )= 46.42^0

This angle is angle from normal, so angle seen by fisherman from horizontal = 90 - 46.42 = 43.58^{0}

5 0
3 years ago
The standard normal curve is not symmetrical. <br> a. True<br> b. False
FrozenT [24]

Answer;

The above statement is false

Explanation;

Symmetrical distribution, commonly known as symmetric distribution or normal distribution, is typically unimodal, meaning it shows only one peak in graph form.

It is a type of distribution where the left side of the distribution mirrors the right side. By definition, a symmetric distribution is never a skewed distribution.

All normal distributions are symmetric and have bell-shaped density curves with a single peak.

7 0
3 years ago
Read 2 more answers
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