Solve the second equation for I_1 and the third equation for I_3. Then plug those into the first equation. From here you can solve for I_2. Then you can plug that in to equation 2 to solve for I_1. Then plug in to equation 3 to solve for I_3.
Answer:
a)the arrow will have a very little kinetic energy after the archer and its realesead the string in the picture of the right
Explanation: you are at my same school and I pass it correct also as shown in the image it should be like that
Answer:
b.
Explanation:
It's b I sis thebksqjwnsx0qkqnsnd991isnd
The two displacement functions are
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s
The distance between the two objects is
x = x₁ - x₂
= 4t + 161 - 48t + 4t²
x = 4t² - 44t + 161
Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
= 4[ (t - 5.5)² - 5.5² ] + 161
x = 4(t-5)² + 40
Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.
Answer: The distance of the closest approach is 40 m.
A. the medium
For refraction to occur, there has to be change from one medium to another. For example rays of light would refract as the travel from air to water.