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EleoNora [17]
3 years ago
13

RANGKAIAN RLC SERI PADA TEGANGAN BOLAK BALIK 220V R=80 OHM XL= 90 OHM XC = 30 OHM MAKA TEGANGAN PADDA INDUKTOR ADALAH???

Physics
1 answer:
Whitepunk [10]3 years ago
8 0
Okay, 90% of this is nonsense besides the numbers maybe.
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Which coefficient is needed in front of NaNO3 to balance the equation Na2S + Zn(NO3)2 → ZnS + _NaNO3? 1, 2, 5, 7,
maksim [4K]

The coefficient is needed in front of NaNO3 to balance the equation is 2.

<h3>What is balanced equation?</h3>

When in a chemical reaction, both the product elements or compounds should have number of moles equal to that of the elements or compounds of reactants.

In the given chemical reaction equation,

Na2S + Zn(NO3)2 → ZnS + _NaNO3

Number of moles of S is 1 on both the product and reactant side. Zn has 1 mole on both side. NO3 has 2 mole and Na has 2 mole on reactant side. So to balance the equation, Na and NO3 both must have 2 moles on product side.

Thus, the coefficient is needed in front of NaNO3 to balance the equation is 2.

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2 years ago
What the balance electrons for calcium​
soldi70 [24.7K]

Answer:

its two valence electrons

Explanation:

Calcium is a group 2 element with two valence electrons. Therefore, it is very reactive and gives up electrons in chemical reactions.

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5 0
3 years ago
A person is standing on an elevator initially at rest at the first floor of a high building. The elevator then begins to ascend
GREYUIT [131]

Answer:

The found acceleration in terms of h and t is:

a=\frac{h}{5(t_1)^2}

Explanation:

(The complete question is given in the attached picture. We need to find the acceleration in terms of h and t in this question)

We are given 3 stages of movement of elevator. We'll first model them each of the stage one by one to find the height covered in each stage. After that we'll find the total height covered by adding heights covered in each stage, and equate it to Total height h. From that we can find the formula for acceleration.

<h3></h3><h3>Stage 1</h3>

Constant acceleration, starts from rest.

Distance = y = \frac{1}{2}a(t_1)^2

Velocity = v_1=at_1

<h3>Stage 2</h3>

Constant velocity where

Velocity = v_o=v_1=at_1

Distance =

<h3>y_2=v_2(t_2)\\\text{Where~}t_2=4t_1 ~\text{and}~ v_2=v_1=at_1\\y_2=(at_1)(4t_1)\\y_2=4a(t_1)^2\\</h3><h3 /><h3>Stage 3</h3>

Constant deceleration where

Velocity = v_0=v_1=at_1

Distance =

y_3=v_1t_3-\frac{1}{2}a(t_3)^2\\\text{Where}~t_3=t_1\\y_3=v_1t_1-\frac{1}{2}a(t_1)^2\\\text{Where}~ v_1t_1=a(t_1)^2\\y_3=a(t_1)^2-\frac{1}{2}a(t_1)^2\\\text{Subtracting both terms:}\\y_3=\frac{1}{2}a(t_1)^2

<h3>Total Height</h3>

Total height = y₁ + y₂ + y₃

Total height = \frac{1}{2}a(t_1)^2+4a(t_1)^2+\frac{1}{2}a(t_1)^2 = 5a(t_1)^2

<h3 /><h3>Acceleration</h3>

Find acceleration by rearranging the found equation of total height.

Total Height = h

h = 5a(t₁)²

a=\frac{h}{5(t_1)^2}

6 0
4 years ago
If you want the ball to land in your hand when it comes back down, should you toss the ball straight upward, in a forward direct
denpristay [2]

Straight upward

the ball moves in the forward direction with your walking speed at all times. If you want the ball to land in your hand when it comes back down, you should toss the ball straight upward.

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Projectile motion is the motion of an object thrown (projected) into the air.

  • After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory

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