(x^2+3x^2-10x-24)/(x+2)
(4x^2-10x-24)/(x+2)
4x^2-10x-24=0
2x^2-5x-12=0
2x^2-5x-12/(x+2)
2x=(2x^2-5x)-(2x^2+4x)>>-9x-12
2x-9=(-9x-12)-(-9x-18)
2x-9=6
4x-18=12>>4x-6
(x-4)(2x+3) is the factorization
Y = -3x - 1......so we sub in -3x - 1 in for y in the other equation
2x + 5y = 12
2x + 5(-3x - 1) = 12....now distribute the 5 through the parenthesis
2x - 15x - 5 = 12...add 5 to both sides
2x - 15x = 12 + 5..combine like terms
-13x = 17...divide both sides by -13
x = -17/13
now sub in -17/13 for x in the other equation
y = -3x - 1
y = -3(-17/13) - 1
y = 51/13 - 1
y = 51/13 - 13/13
y = 38/13
so the solution is (-17/13, 38/13)
Answer:
His gain percent is 20%
Step-by-step explanation:
In this question, we want to find the percentage gain of the business.
We need the following parameters;
The cost price which is the sum of the amount she bought the goods + the amount spent on transport
Using the values we have in the question;
The cost price will be;
13,600 + 400 = Rs 14,000
The selling price = Rs 16,800
Mathematically the percentage gain will be;
% gain = (selling price- cost price)/selling price * 100%
% gain = (16,800-14,000)/14,000 * 100/1
% gain = 2800/14,000 * 100/1 = 1/5 * 100/1 = 20%
150 degrees
hope this helps
