Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
Try comparing your solution with the following:
Solution:
Answer:
Check:
<em>Hope this was helpful.</em>
Answer: The correct answer is -2,5/2 which is the last answer.
Step-by-step explanation:
* Hopefully the work below helps:)Mark me the brainliest:)!!
Use the general form:-
(x - a)^2 + (y - b)^2 = r^2 where (a, b) is the centre and r = radius
Here the radius = 1/2 * 6 = 3 so r^2 = 9 and we have the equation:-
(x + 4)^2 + (y - 2)^2 = 9 (answer)