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scoundrel [369]
4 years ago
14

Calculate the number of kg in 7.66 x 10-5 Gigagrams.

Chemistry
1 answer:
bonufazy [111]4 years ago
6 0

Answer:

76,6 kg

Explanation:

A kg it's equal to 1x10^3 grams

A Gigagrams it's equal to 1x10^9 grams

Knowing this, a kg it's equal to 1x10^6 gigagrams

7,66*10^{-5}[gigagram]*\frac{1*10^6 [kg]}{1 [gigagram]}= 76.6 [kg]

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Choose the correct name for each acid. Click here
Zigmanuir [339]

Answer:

1. Nitrous Acid

2. Hydroiodic Acid

3. Phosphoric Acid

Explanation:

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7 0
3 years ago
Read 2 more answers
Now examine salts containing the halide anions, cl- and br-. Most of these are soluble. What two cations listed lead to insolubl
tatiyna

Ag+ and Pb+2 are two cations that are suggested as producing insoluble halide salts when studying salts containing the halide anions, cl- and br-. First, the charge's number is provided.

Neutral binary salts, also referred to as halide salts, are mixtures of metals and non-metals. The non-metal behaves in a reduced oxidation state at all times. They are the outcome of mixing a hydroxide and hydracid. halide salts of haloids are produced by the reaction of a hydroxide and a hydracid.

Ions are cations with positive charges. They emerge when the electrons of an elemental metal are lost. However, they don't lose any protons; they only lose one or more electrons. To denote a cation, the charge is superscripted following the element name or chemical formula.

Learn more about halide salts here

brainly.com/question/20815131

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8 0
2 years ago
A compound with the empirical formula CH 2 O has a formula mass of 180 g/mol. What is its molecular formula
olga nikolaevna [1]

Empirical formula mass

  • 12+2(1)+16
  • 28+2
  • 30g/mol

Molecular fornula mass:-180g/mol

  • n=Molecular formula mass/Empirical formula mass
  • m=180/30
  • n=6

Molecular formula:-

  • n×Empirical formula
  • 6(CH_2O
  • C_6H_12 O_6
5 0
2 years ago
Cobalt-63 has a half-life of 5.3 years. If a pellet that has been in storage for 15.9 years contains 40.0g of Cobalt-63, how muc
Cerrena [4.2K]

Answer:

320 g  

Step-by-step explanation:

The half-life of Co-63 (5.3 yr) is the time it takes for half of it to decay.  

After one half-life, half (50 %) of the original amount will remain.  

After a second half-life, half of that amount (25 %) will remain, and so on.  

We can construct a table as follows:  

  No. of               Fraction         Mass

half-lives   t/yr   Remaining   Remaining/g

      0        0              1

      1         5.3           ½

     2        10.6           ¼

     3        15.9           ⅛                 40.0

     4        21.2           ¹/₁₆

We see that 40.0 g remain after three half-lives.

This is one-eighth of the original mass.

The mass of the original sample was 8 × 40 g = 320 g

5 0
3 years ago
Calculate the hydroxide ion concentration of a 0.200 M solution of HCIO4
Aleksandr [31]

The concentration of hydroxide ion is  5  \times 10^ − 14  M.

<u>Explanation:</u>

Consider the equilibrium of this acid's dissociation,

                          H C l O 4  ⇌  H +  +  C l O  4 -

Moreover, let's assume that  H C l O 4  is a strong acid and will fully dissociate.

Hence,

                              [ H + ]  =  0.20  M

Now, recall,  

                  K w  =  [ H + ] [ O H − ]  =  1.0  \times 10 ^− 14

Hence,

                  ⇒ [ O H − ]  =  K w  / [ H + ]  = 5  \times 10^ − 14  M.

7 0
4 years ago
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