Mg gives up two to become Mg++
it gives omne each to two different iodines which become I-<span>the compound is MgI2 </span>
Answer : The equilibrium concentration of is, 1.0 M
Explanation : Given,
Equilibrium concentration of = 0.26 M
Volume of solution = 1.00 L
Equilibrium constant = 4.0
The balanced equilibrium reaction will be,
The expression of equilibrium constant for the reaction will be:
From the reaction we conclude that the concentration of and are equal.
Let the concentration of be 'X'.
So, concentration of = X
Now put all the values in this expression, we get :
Thus,
The concentration of at equilibrium = X = 1.0 M
The concentration of at equilibrium = X = 1.0 M
Answer:
The answer is a gamma particle.
<u>Answer:</u> The total vapor pressure of the solution is 81.3 mmHg
<u>Explanation:</u>
To calculate the total pressure, we use the equation given by Dalton and Raoults, which is:
where,
= total vapor pressure
We are given:
Mole fraction of benzene = 0.580
Mole fraction of toluene = (1 - 0.580) = 0.420 (Total mole fraction is always equation to 1)
Vapor pressure of benzene = 183 mmHg
Vapor pressure of toluene = 59.2 mmHg
Putting values in above equation, we get:
Hence, the total vapor pressure of the solution is 81.3 mmHg
Answer:
8.3 g
Explanation:
Step 1: Write the balanced equation
H₃PO₄ + 3 NH₃ ⇒ (NH₄)₃PO₄
Step 2: Calculate the moles corresponding to 5.5 g of H₃PO₄
The molar mass of H₃PO₄ is 97.99 g/mol.
5.5 g × 1 mol/97.99 g = 0.056 mol
Step 3: Calculate the moles of (NH₄)₃PO₄ produced
The molar ratio of H₃PO₄ to (NH₄)₃PO₄is 1:1. The moles of (NH₄)₃PO₄ produced are 1/1 × 0.056 mol = 0.056 mol.
Step 4: Calculate the mass corresponding to 0.056 moles of (NH₄)₃PO₄
The molar mass of (NH₄)₃PO₄ is 149.09 g/mol.
0.056 mol × 149.09 g/mol = 8.3 g