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3 years ago

Convert 8.9 miles (mi) to inches (in). 1 mi = 5,280 feet (ft); 1 ft = 12 in

1 answer:

5 0

Answer:One mile is also equal to 5,280 feet or 1,760 yards. The mile is a US customary and imperial unit of length. Miles can be abbreviated as mi, and are also sometimes abbreviated as m. For example, 1 mile can be written as 1 mi or 1 m. Inches. An inch is a unit of linear length measure equal to 1 / 12 of a foot or 1 / 36 of a yard.

Explanation:

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the element aluminum forms a cation with the charge fill in the blank 2 . the symbol for this ion is , and the name is fill in t

shtirl [24]

The element aluminum forms a cation with the charge of +3. The symbol for this ion is Al³⁺, and the name is aluminum ion. The number of electrons in this ion 10.

Ions are formed when an atom gains or loses electrons.

Metals form positive ions by a loss of electrons whereas non-metals form negative ions by gaining electrons.

The aluminum ion is formed when aluminum loses three electrons to form Al³⁺ ion which has 10 electrons.

in conclusion, ions are formed by a gain or loss of electrons.

Learn more about ions at: brainly.com/question/490569

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5 0

1 year ago

Does CH3F have a higher boiling point than BRF?

Anna71 [15]

Answer:

The boiling point of the fluoromethane (CH3F) is higher than that of fluorine (F2).

7 0

2 years ago

Suppose of hcl and of o2 are added to an empty flask. How much will be in the flask at equilibrium?A. None. B. Some, but less th

serg [7]

This is an incomplete question, here is a complete question.

Hydrogen chloride and oxygen react to form water and chlorine, like this:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

Use this chemical equation to answer the questions in the table below.

Suppose 155. mmol of HCl and 38.8 mmol of O₂ are added to an empty flask. How much HCl will be in the flask at equilibrium?

(1) None.

(2) Some, but less than 155. mmol,

(3) 155. mmol,

(4) More than 155. mmol,

Answer : The correct option is, (1) None

Explanation :

The given balanced chemical reaction is:

$4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)$

From the balanced chemical reaction, we conclude that

As, 4 mmole of HCl react with 1 mmoles of $O_2$

So, 155. mmole of HCl react with $\frac{155.}{4}\times 1=38.75$ mmoles of $O_2$

That means, $O_2$ is excess reagent and $HCl$ is a limiting reagent. All the moles of HCl will consume.

Hence, the correct option is, None.

7 0

3 years ago

2C2H6 + 7O2 ------> 4CO2 + 6H2O

Romashka-Z-Leto [24]

We convert the masses of our reactants to moles and use the stoichiometric coefficients to determine which one of our reactants will be limiting.

Dividing the mass of each reactant by its molar mass:

(10 g C2H6)(30.069 g/mol) = 0.3326 mol C2H6

(10 g O2)(31.999 g/mol) = 0.3125 mol O2.

Every 2 moles of C2H6 react with 7 moles of O2. So the number of moles of O2 needed to react completely with 0.3326 mol C2H6 would be (0.3326)(7/2) = 1.164 mol O2. That is far more than the number of moles of O2 that we are given: 0.3125 moles. Thus, O2 is our limiting reactant.

Since O2 is the limiting reactant, its quantity will determine how much of each product is formed. We are asked to find the number of grams (the mass) of H2O produced. The molar ratio between H2O and O2 per the balanced equation is 6:7. That is, for every 6 moles of H2O that is produced, 7 moles of O2 is used up (intuitively, then, the number of moles of H2O produced should be less than the number of moles of O2 consumed).

So, the number of moles of H2O produced would be (0.3125 mol O2)(6 mol H2O/7 mol O2) = 0.2679 mol H2O. We multiply by the molar mass of H2O to convert moles to mass: (0.2679 mol H2O)(18.0153 g/mol) = 4.826 g H2O.

Given 10 grams of C2H6 and 10 grams of O2, 4.826 g of H2O are produced.

8 0

3 years ago

If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres, what is the volume of the gas?

iVinArrow [24]

If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres the volume of the gas 1.66 litres.

Explanation:

Data given:

number of moles of the gas = 0.725

temperature = 105 K

pressure = 3.75 atm

volume of the gas =?

R = 0.08206 Latm/mole Kelvin

Applying the ideal gas law to calculate the volume of the given gas:

PV = nRT

rearranging the equation to calculate volume:

V = $\frac{nRT}{P}$

putting the values in the equation:

V = $\frac{0.08206 X 0.725 X 105}{3.75}$

V = 1.66 Litres.

At a temperature of 105 K and pressure of 3.75 atm, 0.725 moles of gas occupy 1.66 litres of volume.

6 0

3 years ago