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Amanda [17]
3 years ago
10

Which of the following is/are true regarding initial and maximal velocity of enzyme-mediated reactions?

Chemistry
1 answer:
kenny6666 [7]3 years ago
7 0

Answer:

a. True

b. True

c. False

d. True

Explanation:

a). A a very low substrate concentration , $S. Thus according to the Machaelis-Menten equation becomes

$V_0 = \frac{V_{max} \times [S]}{Km}$

Here since the $V_0$ varies directly to the substrate concentration [S], the initial velocity is lower than the maximal velocity. Thus option  (a) is true.

b). The Michaelis -Menten kinetics equation states that :

   $V_0 = \frac{V_{max} \times [S]}{Km+[S]}$

  Here the initial velocity changes directly with the substrate concentration as $V_0$ is directly proportional to [S]. But $V_{max}$ is same for any particular concentration of the enzymes. Thus, option (b) is true.

c). As the substrate concentration increases, the initial velocity also increases. Thus option (c) is false.

d). Option (d) explains the procedures to estimate the initial velocity which is correct. Thus, option (d) is true.

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Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
3 years ago
A pharmaceutical company is making a large volume of nitrous oxide (NO). They predict they will be able to make a maximum amount
iragen [17]

Answer:

The answer is "Option B"

Explanation:

From the query, the following knowledge is derived:  

Yield in percentage = 47%  

Performance of theory = 4860 g  

Actual yield Rate =?  

The percentage return is defined simply by the ratio between both the real return as well as the conceptual return multiplied by the 100. It's also represented as numerically:

Rate = \frac{Existing \ Rate} {Theoretical \ Rate} \times 100

Now We can obtain the percent yield as followed using the above formula:  

\text{Yield in percentage}= \frac{Actual \ yield \ Rate} {Theorical \ Rate} \times  100

47\% = \frac{Actual \ yield \ Rate}{4860}

The value of the Actual yield Rate =47\% \times 4860

                                                        = \frac{47}{100} \times 4860 \\\\ = 2284.2 g

The Actual yield Rate= 2284.2 g.

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3 years ago
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6 0
3 years ago
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An Erlenmeyer flask contains 25.00 mL of 0.500 M HCl before a titration is begun. How many moles of hydrogen ions are present in
Sliva [168]

Answer:

0.0125 mol.

Explanation:

<em>Molarity of a solution is the no. of moles of a solute per 1.0 L of the solution.</em>

<em></em>

M of HCl = 0.5 mol/L.

V = 25.0 mL = 0.025 L.

<em>∴ no. of moles of HCl present in the flask at this time = MV</em> = (0.5 mol/L)(0.025 L) = <em>0.0125 mol.</em>

6 0
3 years ago
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