All categories

4 years ago

Classify each property as intensive or extensive. Color, temperature, volume, hardness, mass, boiling point, length, density

Chemistry

2 answers:

lisov135 [29]4 years ago

8 0

Explanation:

When amount of matter changes in a substance then a physical property that does not change due to this is known as an intensive property.

For example, density, color, boiling point, hardness etc are all intensive properties.

Whereas property of a substance that changes due to change in amount of matter of a substance is known as extensive property.

For example, temperature, volume etc are all extensive properties.

Hence, we can conclude that given properties are classifies as follows.

Intensive property : color, hardness, boiling point, density, temperature.

Extensive property : length, volume, mass.

mr_godi [17]4 years ago

3 0

Answer:

Intensive properties can be used to help identify a sample because these characteristics do not depend on the amount of sample, nor do they change according to conditions.

Explanation:

Intensive properties are bulk properties, which means they do not depend on the amount of matter that is present. Examples of intensive properties include:

Boiling Point

Density

State of Matter

Color

Melting Point

Odor

Temperature

Refractive Index

Luster

Hardness

Ductility

Malleability

You might be interested in

All living organisms are made out of cells. Select three cell parts that all cells contain.

algol [13]

Answer:

cell membrane, ribosomes and dna..?

5 0

3 years ago

What pressure (in atm) is required to contain 0.034 moles of oxygen gas in a 5.1 L container at a temperature of 25.00C

kherson [118]

Answer:

0.16 atm

Explanation:

Let's look at the formula PV=nRT. First of all, T should be in kelvin, so let's add 273. Now solve for P so we get P = nRT/V.

Now let's plug these in...

P = (0.034 mol)(0.08206 L atm mol^-1 K^-1)(298 K)/5.1 L

After solving and rounding to sig figs we get 0.16 atm

5 0

2 years ago

What is the specific latent heat of fusion for a substance that takes 550 KJ to melt 14 KG at 262 K?

Arte-miy333 [17]

Answer:- The right choice is A. $3.9*10^4\frac{J}{kg}$ .

Solution:- Latent heat of fusion means the heat required to melt the solid at constant temperature means there is no change in temperature only the solid changes to liquid. So, it is a solid to liquid phase change.

$q=m*\Delta H_f_u_s$

where q is the heat required to convert solid to liquid, m is the mass and $\Delta H_f_u_s$ is the latent heat of fusion.

From given info, 550 kJ that is 550000 J of heat is required to melt 14 kg of solid at 262K temperature. Let's rearrange the equation for latent heat of fusion and plug in the values in it.

$\Delta H_f_u_s=\frac{q}{m}$