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3 years ago

Classify each property as intensive or extensive. Color, temperature, volume, hardness, mass, boiling point, length, density

Chemistry

2 answers:

lisov135 [29]3 years ago

8 0

Explanation:

When amount of matter changes in a substance then a physical property that does not change due to this is known as an intensive property.

For example, density, color, boiling point, hardness etc are all intensive properties.

Whereas property of a substance that changes due to change in amount of matter of a substance is known as extensive property.

For example, temperature, volume etc are all extensive properties.

Hence, we can conclude that given properties are classifies as follows.

Intensive property : color, hardness, boiling point, density, temperature.

Extensive property : length, volume, mass.

mr_godi [17]3 years ago

3 0

Answer:

Intensive properties can be used to help identify a sample because these characteristics do not depend on the amount of sample, nor do they change according to conditions.

Explanation:

Intensive properties are bulk properties, which means they do not depend on the amount of matter that is present. Examples of intensive properties include:

Boiling Point

Density

State of Matter

Color

Melting Point

Odor

Temperature

Refractive Index

Luster

Hardness

Ductility

Malleability

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3 years ago

A certain half-reaction has a standard reduction potential +0.80 V . An engineer proposes using this half-reaction at the anode

Strike441 [17]

Answer:

a. Minimum 1.70 V

b. There is no maximum.

Explanation:

We can solve this question by remembering that the cell potential is given by the formula

ε⁰ cell = ε⁰ reduction - ε⁰ oxidation

Now the problem states the cell must provide at least 0.9 V and that the reduction potential of the oxidized species 0.80 V, thus

ε⁰ reduction - ε⁰ oxidation ≥ ε⁰ cell

Since ε⁰ oxidation is by definition the negative of ε⁰ reduction , we have

ε⁰ reduction - ( 0.80 V ) ≥ 0.90 V

⇒ ε⁰ reduction ≥ 1.70 V

Therefore,

(a) The minimum standard reduction potential is 1.70 V

(b) There is no maximum standard reduction potential since it is stated in the question that we want to have a cell that provides at leat 0.9 V

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3 years ago

The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is DDT . H

Vlad1618 [11]

Answer: 0.028 grams

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

$\Delta T_f=k_f\times m$

or,

$\Delta T_f=k_f\times \frac{\text{ Mass of solute in g}\times 1000}{\text {Molar mass of solute}\times \text{ Mass of solvent in g}}$

where,

$\Delta T_f$ = change in freezing point

$k_f$ = freezing point constant (for benzene} = $5.12^0Ckg/mol$

m = molality

Putting in the values we get:

$0.400^0C=5.12\times \frac{\text{ Mass of solute in g}\times 1000}{354.5\times 209.0}$

${\text{ Mass of solute in g}}=0.028g$

0.028 grams of DDT (solute) must be dissolved in 209.0 grams of benzene to reduce the freezing point by 0.400°C.

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3 years ago

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Molodets [167]

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3 years ago

15. If you dilute a 6 M solution of HCl from 5 mL to 50mL, what is the concentration of this new solution? (M1V1 = M2V2)

Andreyy89

Answer:

B) 0.6M

Explanation:

I apologize in advance if it is not correct :l

The (M1V1= M2V2) is given for you to plug in the correct numbers so let's jot this down.

(M1*V1= M2*V2)

so they give us 6M which would be our (M1), from this we can also conclude that 5mL is also V1; ( if you notice the M1's and V1's are always found next to eachother). This leads us to our 50mL, this would be our V2 because the volume went from 5mL to 50mL. Now lets put this in order based on what we know.

M1= 6M (M1*V1= M2*V2)

V1= 5mL

M2= ?

V2= 50mL

now we plug in what we know into the equation to find the unknown (M2)

(6M*5mL= M2*50mL)

now we could do the long math, but I don't think your on brainly to do the hard way. so lets keep it simple!

We are going to put the 50mL under the (6M*5mL) for division.

$\frac{(6M*5mL)}{(50mL)}$ This is honestly MUCH easier, than manually answering. you just put that in the calculator and it'll give you B) 0.6M

honestly though I might not know what I'm doing cuz im currently doing my test and decided to answer this question ;)

Good Luck!

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3 years ago