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3 years ago

Convert 1.50μm2 to square meters

1 answer:

4 0

1 micro meter = $10^{-6} meters$
1 μm ^2 = 1 μm*1μm = $10^{-6} *10^{-6} = 10^{-12}$ meters

1.5 μm^2 = 1.5 * $10^{-12}$ meters

μm^2 is a unit for surface. First you want to convert μm to meters which is unit for length and if you multiply units for length you get unit for surface.

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What mass of Cl2, in grams is contained in a 10.0L tank at 27oC and 3.50 atm pressure ? a. 1.42 grams b. 142 grams c. 1.01 kg d.

Evgen [1.6K]

Answer:

the correct answer is A

Explanation:

8 0

3 years ago

How many particles are in 12.47 grams of NaCl?

jeka94

If we are talking about moles then the answer to that is 0.22

5 0

3 years ago

Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =

Arada [10]

Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Wherem

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314 J / K mol

Thus, given that, $E_a$ = ?

$k_2=4.0\times 10^3s^{-1}$

$k_1=1.5\times 10^3s^{-1}$

$T_1=5\ ^0C$

$T_2=25\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (5 + 273.15) K = 278.15 K

T = (25 + 273.15) K = 298.15 K

$T_1=278.15\ K$

$T_2=298.15\ K$

So,

$\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)$

$E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}$

$E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}$

$E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}$

$E_a=33813.28\ J/mol$

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

8 0

3 years ago

What is the molarity of a solution prepared by dissolving 2.5 grams of LiNO3 in sufficient water to make 60.0 mL of solution?

Murrr4er [49]

Answer: hope this helps

To make molar NaCl solutions of other concentrations dilute the mass of salt to 1000ml of solution as follows:

0.1M NaCl solution requires 0.1 x 58.44 g of NaCl = 5.844g.

0.5M NaCl solution requires 0.5 x 58.44 g of NaCl = 29.22g.

2M NaCl solution requires 2.0 x 58.44 g of NaCl = 116.88g.

Explanation:

6 0

3 years ago

Read 2 more answers

I will mark brainliest<br> What are dams? How do they help conserve water?

Gre4nikov [31]

Answer: what are dams?

A dam is a barrier that stops or restricts the flow of water or underground streams. Reservoirs created by dams not only suppress floods but also provide water for activities such as irrigation.

how does it conserve water?

well there could be many ways it can conserve water but I will tell you the most important.

When the water level increases they open gates in order to send out water. These dams allow us to store and not to drain water into oceans soon. A DAM is a barrier constructed to hold back water and raise its level

Explanation:

I hope this helps plz click the heart and mark me braines!

have a wonderful day!

7 0

3 years ago