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ladessa [460]
3 years ago
5

Which of the following hydrocarbons has a double bond in its carbon skeleton?1) C3H82) C2H63) CH44) C2H45) C2H2

Chemistry
1 answer:
Kipish [7]3 years ago
8 0

Answer:

  • <u>C₂H₄</u>  (option number 4)

Explanation:

A hydrocarbon with a <em>double bond</em> in its carbon skeleton is an alkene and has the general form:

  • C_nH_{2n}.

This is, the number of hydrogen atoms is twice the number of carbon atoms.

On the other hand, alkanes have only single bonds, and the compounds with a triple bond in its carbon skeleton are alkynes.

Review each choice:

1) <u>C₃H₈:</u>

  • In this case, the number of hydrogen atoms is 2×3 + 2 = 6 + 2 = 8, which is corresponds to an alkane, not an alkene.

2)<u> C₂H₆</u>

  • For this, the number of hydrogen atoms is 2 × 2 + 2 = 4 + 2 = 6. Again an alkane, not alkene.

3) <u>CH₄</u>

  • Hydrogen atoms: 1 × 2 + 2 = 4 ⇒ an alkane

4) <u>C₂H₄ </u>

  • Hydrogen atoms: 2 × 2  = 4.  This is precisely the relation for an alkene, so this is the hydrocarbon that has a double bond in its carbon skeleton.

  • The chemical formula may be writen as CH₂ = CH₂, to show the double bond.

So, this is the correct answer.

5) <u>C₂H₂</u>

  • Hydrogen atoms: 2 × 2 - 2 = 4 - 2 = 2. This relation of carbon and hydrogen atoms corresponds to a compound with triple bond, i.e an alkyne: CH≡CH.
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blagie [28]

a)

A: Copper

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E: $\mathrm{CO_2}$

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b)

$\mathrm{CuO+ H_2SO_4}\rightarrow \mathrm{CuSO_4 + H_2O}$

c)

$\mathrm{CuCO_3+ 2HNO_3}\rightarrow \mathrm{Cu(NO_3)_2+ CO_2+ H_2O}$

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CK-12 Boyle and Charles's Laws if Mrs. Pa pe prepares 12.8 L of laughing gas at 100.0 k Pa and -108 °C and then she force s the
nirvana33 [79]

Answer:

The answer to your question is   P2 = 2676.6 kPa

Explanation:

Data

Volume 1 = V1 = 12.8 L                        Volume 2 = V2 = 855 ml

Temperature 1 = T1 = -108°C               Temperature 2 = 22°C

Pressure 1 = P1 = 100 kPa                    Pressure 2 = P2 =  ?

Process

- To solve this problem use the Combined gas law.

                     P1V1/T1 = P2V2/T2

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                     P2 = P1V1T2 / T1V2

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T1 = -108 + 273 = 165°K

T2 = 22 + 273 = 295°K

- Convert volume 2 to liters

                       1000 ml -------------------- 1 l

                         855 ml --------------------  x

                         x = (855 x 1) / 1000

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Hitman42 [59]

Answer:

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Explanation:

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Electronic configuration of chlorine:

Cl₁₇ = 1s² 2s² 2p⁶ 3s² 3p⁵

Abbreviated electronic configuration:

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1. it is greenish-yellow irritating gas.

2. its melting point is 172.2 K

3. its boiling point is 238.6 K

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