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gtnhenbr [62]
3 years ago
5

A 55.0-g aluminum block initially at 27.5 degree C absorbs 725 J of heat. What is the final temperature of the aluminum? Express

your answer in degrees Celsius to one decimal place.
Physics
1 answer:
andrew11 [14]3 years ago
6 0

Answer:

Final temperature of the aluminum = 41.8 °C

Explanation:

We have the equation for energy

      E = mcΔT

Here m = 55 g = 0.055 kg

ΔT = T - 27.5

Specific heat capacity of aluminum = 921.096 J/kg.K

E = 725 J

Substituting

     E = mcΔT

     725 = 0.055 x 921.096 x (T - 27.5)

     T - 27.5 = 14.31

     T = 41.81 ° C = 41.8 °C

Final temperature of the aluminum = 41.8 °C

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Hello, I am so confused about this problem, could you help ?
iVinArrow [24]

Given:

The masses of the balls, m₁=1 kg

m₂=2 kg

The height of 1 kg ball, h₁=6 m

The height of 2 kg ball, h₂=3 m

To find:

Which of the given statements are true?

Explanation:

From the law of conservation of energy, the energy can neither be created nor be destroyed. As the air resistance is negligible, the initial potential energy of the balls will be equal to their kinetic energy when they reach the ground.

Thus, the kinetic energy of the balls when they reach the ground is given by,

KE=PE=mgh

Where m is the mass of the balls, h is their respective height, and g is the acceleration due to gravity.

Thus the kinetic energy of mass m₁ is,

\begin{gathered} KE_1=1\times9.8\times6 \\ =58.8\text{ J} \end{gathered}

The kinetic energy of mass m₂ is,

\begin{gathered} KE_1=2\times9.8\times3 \\ =58.8\text{ J} \end{gathered}

The velocities of the balls will be given by the equation of kinetic energy.

Thus,

KE=\frac{1}{2}mv^2

Where v is the respective velocities of the balls when they reach the ground.

On rearranging the above equation, the velocities will be given by,

v=\sqrt{\frac{2\times KE}{m}}

On substituting the known values, the velocity of the mass m₁ is

\begin{gathered} v_1=\sqrt{\frac{2\times58.8}{1}} \\ =10.84\text{ m/s} \end{gathered}

The velocity of the mass m₂ is,

\begin{gathered} v_2=\sqrt{\frac{2\times58.8}{2}} \\ =7.7\text{ m/s} \end{gathered}

Thus the balls will have the same kinetic energies when they reach the ground. But the 1 kg ball will have a greater velocity than the 2-kg ball.

The time interval the ball takes is dependent on the height only and not on the mass. Thus the balls will not reach the ground at the same time.

Final answer:

Thus the correct answer is options are option B and option D.

6 0
1 year ago
How many meters in 2.50 miles? (Use these two conversions: 1000 m = 1 km and 1.00 km = .621 mi )
Artyom0805 [142]

2.50 miles is equal to 4026 m.

<u>Explanation:</u>

As it is known that 1000 m =1 km and 1 km = 0.621 miles. So first we have to convert miles to km and then to metre as follows.

As 1 km = 0.621 miles, then

             \text { 1 miles }=\frac{1}{0.621} \mathrm{km}

So, 2.50 miles will be equal to

            2.50 \text { miles }=\frac{2.50}{0.621} \mathrm{km}=4.026 \mathrm{km}

Then, in order to get the answer in meters, we have to convert this km to meter by the conversion of 1000 m =1 km.  So,

           1 \mathrm{km}=1000 \mathrm{m}

Thereby,

          4.026 \mathrm{km}=4026 \mathrm{m}

7 0
3 years ago
a horse stands on a flat surface if the horse has a mass of 186 kg what is the normal force acting on it
astra-53 [7]
The mass of the horse is 186 kg.

The weight of the horse is
(186 kg)*(9.8 m/s^2) = 1822.8 N

According to Newton's 3rd Law, there is an equal and opposite force between the horse and the surface.
Therefore the normal reactive force is 1822.8 N.

Answer: 1822.8 N

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