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madam [21]
3 years ago
14

An object is placed 50.0 cm in front of a convex mirror. where can be the image located if the focal length is 40 cm from the mi

rror
Need now plz and thank you! ​
Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

Image will form at distance 22.22 cm behind the mirror

Explanation:

As we know that the mirror formula is given as

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

now we know that

object distance from mirror is

d_o = -50 cm

Focal length of the mirror is given as

f = 40 cm

now we have

\frac{1}{-50} + \frac{1}{d_i} = \frac{1}{40}

\frac{1}{d_i} = \frac{1}{50} + \frac{1}{40}

d_i = 22.22 cm

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My name is Ann [436]

Answer:

Angle of incidence that entered material b= 63.1°

Angle of incidence between a and b = 55.9°

Explanation: Using the formular:

n1sintheta1= n2sintheta2

The light ray which enters material B will be

1.4Sin72.8° = 1.5Sin theta

1.3373= 1.5Sintheta

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When the ray hits interface with material a

1.5Sin63.1 = 1.3 Sin theta

1.3374 = 1.3Sin theta

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Sin theta = 1.0877

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The equation should be

1.4sin63.1 = 1.4 sin theta

Sin theta=72.8°

When the ray hits air-c boundary:

1.4sin72.8=1.00sin theta

Sin theta=1.3374/1 =1.3374

There is total reflection.

In material a,the ray will:

1.3sin72.8° = 1.00sin theta

There will be total reflection when the ray hits a-b boundary.

1.3sin72.8= 1.5sintheta

Sin theta= 1.2419/ 1.5

Sin theta =0.8279

Theta= Sin^-10.8279= 55.88°

When ray hits c-air boundary

1.4sin63.1= 1.00sintheta

1.2485= sin theta = Toal reflection.

Therefore when the ray of light pass through the layers of material a, b and c the boundary with air on top and bottom will be total reflection.

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