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erma4kov [3.2K]
3 years ago
7

A 3.00 watt electric motor is plugged into an electrical outlet It takes the motor 30 00 seconds to lift a mass of 254.9 g a dis

tance of
10.00 cm. In that time, the motor has used 90.00 J of energy Assuming no energy leaves the system, how much heat has been
added to the system by the end of those 30 seconds?​
Physics
1 answer:
trasher [3.6K]3 years ago
8 0

Answer:

89.75 J

Explanation:

The motor uses 90.00 J of electrical energy.  Any of that energy that isn't used to do work is converted to heat.

The amount of work done is:

W = mgh

W = (0.2549 kg) (9.81 m/s²) (0.1000 m)

W = 0.2501 J

So the heat generated is:

Q = 90.00 J − 0.2501 J

Q = 89.75 J

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Please help me, this is a physics test.
sweet-ann [11.9K]

Answer:

a = 2 [m/s²]

Explanation:

To be able to solve this problem we must make it clear that the starting point when the time is equal to zero, the velocity is 5 [m/s] and when three seconds have passed the velocity is 11 [m/s], this point is the final point or the final velocity.

We can use the following equation.

v_{f}=v_{o}+a*t\\

where:

Vf = final velocity = 11 [m/s]

Vo = initial velocity = 5 [m/s]

a = acceleration [m/s²]

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4 0
3 years ago
A 7.94-nC charge is located 1.77 m from a 4.14-nC point charge. (a) Find the magnitude of the electrostatic force that one charg
STatiana [176]

Answer:

F=94.32*10⁻⁹N  , The force F is repusilve because both charges have the same sign (+)

Explanation:

Two point charges (q₁, q₂) separated by a distance (d) exert a mutual force (F) whose magnitude is determined by the following formula:  

F=K*q₁*q₂/d² Formula (1)  

F: Electric force in Newtons (N)

K : Coulomb constant in N*m²/C²

q₁,q₂:Charges in Coulombs (C)  

d: distance between the charges in meters(m)

Equivalence  

1nC= 10⁻⁹C

Data

K=8.99x10⁹N*m²/C²

q₁ = 7.94-nC= 7.94*10⁻⁹C

q₂= 4.14-nC=  4.14 *10⁻⁹C

d= 1.77 m

Magnitude of the electrostatic force that one charge exerts on the other

We apply formula (1):

F=8.99x10^{9} *\frac{7.94*10^{-9} *4.14 *10^{-9} }{1.77^{2} }

F=94.32*10⁻⁹N  , The force F is repusilve because both charges have the same sign (+)

7 0
3 years ago
An object is accelerating at 2m/s^2. What is the net force if the mass is 125kg?
natita [175]

Answer:

250 N

Explanation:

Newton's second law:

∑F = ma

∑F = (125 kg) (2 m/s²)

∑F = 250 N

3 0
3 years ago
The magnitude of a vector can never be less than the magnitude of one of its components. Group of answer choices True False
pogonyaev

Answer:

True

Explanation:

As the formula for magnitude of a vector v and their components v_1, v_2, v_3, v_4,..., v_n is

v^2 = v_1^2 + v_2^2 + ... +v_n^2

Since v_1^2, v_2^2, v_3^2, v_4^2,..., v_n^2 \geq 0, this means the sum of them, v^2, is always greater or equal to v_1^2, v_2^2, v_3^2, v_4^2,..., v_n^2

6 0
3 years ago
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