Answer:
3.44 × 10²⁴ atoms of oxygen
Explanation:
Step 1: Calculate the moles corresponding to 163 g of Al₂(SO₄)₃
The molar mass of Al₂(SO₄)₃ is 342.15 g/mol.
163 g × 1 mol/342.15 g = 0.476 mol
Step 2: Calculate the molecules in 0.476 moles of Al₂(SO₄)₃
We will use Avogadro's number: there are 6.02 × 10²³ molecules of Al₂(SO₄)₃ in 1 mole of Al₂(SO₄)₃.
0.476 mol × 6.02 × 10²³ molecules/1 mol = 2.87 × 10²³ molecules
Step 3: Calculate the atoms of O in 2.87 × 10²³ molecules of Al₂(SO₄)₃
According to the chemical equation, the molar ratio of Al₂(SO₄)₃ to O is 1:12. The atoms of O are 12/1 × 2.87 × 10²³ = 3.44 × 10²⁴.
