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Nataly [62]
3 years ago
5

Uma indústria de confecção de placas de alumínio deseja transportar 100 placas de alumínio para um cliente. Considerando que o v

eículo de transporte pode carregar até 3 toneladas e que a dimensão de cada placa são 2 M X 50 Cm X 2cm Calcule,
Chemistry
1 answer:
Bogdan [553]3 years ago
8 0
Questions:

The questions or computes to do are:

<span>a- a massa, em kg, de cada placa de alumínio;

b- a quantidade mínima de viagens necessárias para que apenas um veículo de transporte entregue o material solicitado ao cliente.

Dado: densidade do alumínio = 2,7 g/cm3

Answer:

a) mass in kg of every aluminum plate

Dimensions of every aluminum plate: </span>
<span>2 M X 50 Cm X 2cm

Volume: 200 cm * 50 cm * 2 cm = 20,000 cm^3

Mass:

density = mass / volume => mass = density * volume = 2.7 g/cm^3 * 20,000 cm^3 = 54,000 g = 54 kg.

Answer: the mass of everyplate of aluminum is 54 kg.

b) number of travels required for one truck deliver all the material:

number of travels = amount requested / amount that a truck can deliver in one travel.

amount requested: 100 plates

mass of 100 plates = 100 plates * 54 kg / plate = 5,400 kg

limit of transport per travel: 3 tons = 3,000 kg

number of travels = 5,400 kg / 3,000 kg/travel = 1.8 travels => 2 travels.

Answer: at least 2 travels.
</span>
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As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.

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The solubility of KNO₃ per 100.0 g of water at 0.0 °C = 14.0 g.

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