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klasskru [66]
2 years ago
14

Which equation illustrates the division property of equality? PLEASE HELP ME!!

Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
8 0
C does.  8f = 40   divide both sides by 8 to get f=5
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I need help on this question please help!!!!!
Tju [1.3M]

Answer:cam

Step-by-step explanation:

7 0
3 years ago
Please ASAP answer this question:)
Darina [25.2K]

Answer:

17 in

Step-by-step explanation:

H²= 8²+15²

H²= 64+225

H²=289

H= √289

H= 17

8 0
2 years ago
Read 2 more answers
Please help me with this question !!!!
AlekseyPX
The distance of DC=HG,4.47; distance of CB=GF, 2.23; distance of BA=FE, 2.23; distance of AD=EH, 3.16


Answer:All sides are congruent so the shapes are congruent

Hope this helps :)
4 0
3 years ago
A group spends $277.50 to rent a total of 15 tubes. How many of each type of tube does the group rent?
tensa zangetsu [6.8K]

The amount spent on each tube is $18.5

The total amount spent to rent 15 tubes by the group is $277.50.

Since they did not specify in the question the types of tubes they rented, we cannot determine each types of tubes that the group rented but we can determine the amount spent on each tube provided that they are all the same types.

∴

if 15 tubes = $277.50

1 tube = $x

By cross multiplying:

\mathbf {\$(x) = \dfrac{ \$277.50 \times 1 \ tube }{15 \ tube}}

\mathbf {(x) = \$18.5}

Therefore, we can conclude that the amount spent on each tube is $18.5

Learn more about arithmetic operations here:

brainly.com/question/15385899?referrer=searchResults

4 0
2 years ago
35 POINTS AVAILABLE
aliina [53]

Answer:

Part 1) The length of each side of square AQUA is 3.54\ cm

Part 2) The area of the shaded region is (486\pi-648)\ units^{2}

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

A=\pi r^{2}

we have

A=25\pi\ cm^{2}

substitute in the formula and solve for r

25\pi=\pi r^{2}

simplify

25=r^{2}

r=5\ cm

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

SU=r=5\ cm

Let

x------> the length side of the square

Applying the Pythagoras Theorem

5^{2}=x^{2} +x^{2}

5^{2}=2x^{2}

x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

A=\pi r^{2}    

we have

r=AB=18\ units

substitute in the formula

A=\pi (18)^{2}=324\pi\ units^{2}

step 2

Find the length of each side of square BCDE

we have that

AB=18\ units

The diagonal DB is equal to

DB=(2)18=36\ units

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

36^{2}=x^{2} +x^{2}

1,296=2x^{2}

648=x^{2}

x=\sqrt{648}\ units

step 3

Find the area of the square BCDE

The area of the square is

A=(\sqrt{648})^{2}=648\ units^{2}

step 4

Find the area of the smaller circle

The area of the circle is equal to

A=\pi r^{2}    

we have

r=(\sqrt{648})/2\ units

substitute in the formula

A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}  

step 5

Find the area of the shaded region

324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}

7 0
3 years ago
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