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3 years ago

How do u work out one quarter of something?

Mathematics

1 answer:

Natalka [10]3 years ago

5 0

One quarter
quarter means 4
so one quarter is 1 out of 4
or the fraction 1/4
or the decimal 0.25

Hope this helps!

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HELP! WILL GIVE BRAINLIEST! DO NOT TAKE ANSWERS OFF ONLINE, THEY ARE WRONG!!!! The following is an incomplete paragraph proving

ohaa [14]

Answer:

The correct option is B.

Step-by-step explanation:

Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .

Draw a diagonal AC.

In triangle BCA and DAC,

AC\cong ACAC≅AC (Reflexive Property of Equality)

\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)

\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)

The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.

By ASA postulate,

\triangle BCA\cong \triangle DAC△BCA≅△DAC

Therefore option B is correct

4 0

3 years ago

Which expression simplifies...

Zina [86]

Answer:

see below

Step-by-step explanation:

If suffices to look at the last term. It must simplify to 4/(3w²), so the exponents of z must match in numerator and denominator, and the ratio of constants must reduce to 4/3.

The exponents of z have the right values in choices B and D, but the ratio of constants only matches in choice D. Looking at the rest of choice D, we see that we can factor 6w²z² from both numerator and denominator, then factor 2 from the remaining numerator to make it match the desired form.

$\dfrac{(12w^2z^4-24w^2z^2)}{18w^4z^2}=\dfrac{6w^2z^2}{6w^2z^2}\cdot\dfrac{2z^2-4}{3w^2}=\dfrac{2(z^2-2)}{3w^2}$

3 0

3 years ago

I need help I can’t figure it out

dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$

7 0

3 years ago

Write with fractional exponents. 6^5 square root x^2 y

sertanlavr [38]

Answer:

6xy^2/5 what im assuming is right

Step-by-step explanation:

4 0

2 years ago

2 + 1/6a = -4 what is a

horsena [70]

Answer:

I found that it was -1, but everything online is telling me -36.

6 0

3 years ago