Answer: Choice C
h(x) = -x^4 + 2x^3 + 3x^2 + 4x + 5
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Explanation:
When reflecting the function f(x) over the y axis, we replace every x with -x and simplify like so
f(x) = -x^4 - 2x^3 + 3x^2 - 4x + 5
f(-x) = -(-x)^4 - 2(-x)^3 + 3(-x)^2 - 4(-x) + 5
f(-x) = -x^4 + 2x^3 + 3x^2 + 4x + 5
h(x) = -x^4 + 2x^3 + 3x^2 + 4x + 5
Note the sign changes that occur for the terms that have odd exponents (the terms -2x^3 and -4x become +2x^3 and +4x); while the even exponent terms keep the same sign.
The reason why we replace every x with -x is because of the examples mentioned below
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Examples:
The point (1,2) moves to (-1,2) after a y axis reflection
Similarly, (-5,7) moves to (5,7) after a y axis reflection.
As you can see, the y coordinate stays the same but the x coordinate flips in sign from negative to positive or vice versa. This is the direct reason for the replacement of every x with -x.
A quadratic equation is in the form of ax²+bx+c. The time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.
<h3>What is a quadratic equation?</h3>
A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.
The complete question is:
A ball is thrown from an initial height of 2 feet with an initial upward velocity of 31 ft/s. The ball's height h (in feet) after 7 seconds is given by the following, h=2+31t-16t². Find all values of t for which the ball's height is 16 feet. Round your answer(s) to the nearest hundredth.
The time at which the height of the ball is 16 feet can be found by,
h = 2 + 31t - 16t²
16 = 2 + 31t - 16t²
16 - 2 - 31t + 16t² = 0
16t² - 31t + 14 = 0

t = 0.717 , 1.221
Hence, the time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.
Learn more about Quadratic Equations:
brainly.com/question/2263981
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Step-by-step explanation:
Simple interest formula

Compound interest formula

a.

Simple interest is $125
b
. 
Compound interest is $125
c. the result for both a and b are the same
d.

the simple interest is $375
e
. ![A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385](https://tex.z-dn.net/?f=A%20%3D%205000%20%281%20%2B%20%5Cfrac%7B0.025%7D%7B1%7D%29%5E%7B1%2A3%7D%5D%20%5C%5CA%3D5000%281.025%29%5E3%20%5C%5CA%3D5000%281.077%29%5C%5CA%3D%205385)
the compound interest is $385
f. the result compared, compound interest is $10 more than simple interest
g.

the simple interest is $600
h.
![A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869](https://tex.z-dn.net/?f=A%20%3D%205000%20%281%20%2B%20%5Cfrac%7B0.02%7D%7B1%7D%29%5E%7B1%2A6%7D%5D%20%5C%5CA%3D5000%281.12%29%5E6%20%5C%5CA%3D5000%281.9738%29%20%5C%5CA%3D%209869)
the compound interest is $4869
i. the result from g and h, h is over 8 times bigger than g.
j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h
Answer:
22 + 2|/2
Step-by-step explanation:
24 - 4|/2 + 6|/2 - |/4
24 + 2|/2 - 2
24 - 2 + 2|/2
22 + 2|/2
note: |/ means root
couldn't find a sign for root so just makeshift with that
hope it helps.