Answer:
Step-by-step explanation:
Since, angle 1 is an exterior angle of ΔABE,
m∠1 > m∠3 and m∠4
Since, angle 1 is an exterior angle of ΔABD,
m∠1 > m∠5
Since, angle 1 is an exterior angle of ΔABC,
m∠1 > m∠7 and m∠8
Therefore, ∠1 is greater than ∠3, ∠5, ∠7 and ∠8.
2/14 in simplest form is 7.
For any distribution, the sum of the probabilities of all possible outcomes must be 1. In this case, we have to have

We're told that
, and we're given other probabilities, so we have

The expected number of calls would be
![E[X]=\displaystyle\sum_xx\,P(X=x)](https://tex.z-dn.net/?f=E%5BX%5D%3D%5Cdisplaystyle%5Csum_xx%5C%2CP%28X%3Dx%29)
![E[X]=0\,P(X=0)+1\,P(X=1)+\cdots+4\,P(X=4)](https://tex.z-dn.net/?f=E%5BX%5D%3D0%5C%2CP%28X%3D0%29%2B1%5C%2CP%28X%3D1%29%2B%5Ccdots%2B4%5C%2CP%28X%3D4%29)
![E[X]=1.4](https://tex.z-dn.net/?f=E%5BX%5D%3D1.4)
10+3=13
70/13=5.384615385
5.384615385*3= 16.15384615
So you would use 16 ounces of flour to 2 sig figs