Answer:
A spring whose spring constant is 200 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required to compress it another 1 inch.
Step 1 of 4
The force at any point during the deflection of the spring is given by,
where is the initial force
and x is the deflection as measured from the point where the initial force occurred.
The work required to compress the spring is
Therefore work required to compress the spring is
The work required to compress the spring in Btu is calculated by
Where 1Btu =778
The work required to compress the spring,
eman Asked on February 19, 2018 in thermal fluid Sciences 4th solutions.
Explanation:
Answer:
69 revolutions
Explanation:
given,
initial angular velocity = 0
final angular velocity = 6 rev/s
when safety switch turned off
tub smoothly slows to rest in (t)= 13 s
total revolution of tub = ?
angular acceleration = 
angular acceleration = 
= 0.6 rev/s²
now,
= 30 revolution
now,
when safety switch turn off
angular acceleration =
angular acceleration = 
= -0.462 rev/s²
now,
= 39 revolution
total revolution = 30 + 39 = 69 revolutions.
tub will rotate 69 revolutions
Answer:
611.064 kJ
Explanation:
Given :
m = 200 mL = 200 g
Specific heat of ice = 2.06 J/g°C
Q = mcΔt
Δt = 0 - (-22) = 22
Q1 = 200 * 2.06 * 22 = 9064 J
Q2 = Melt 0 °C solid ice into 0 °C liquid water:
Q2 = m · ΔHf ; ΔHf = heat of fusion of water = 334j/g
Q2 = 200 * 334 = 66800 J
Q3 : Heat to convert from 0°C to 100°C
Q3 = mcΔt ; c = 4.19 J/g°C ; Δt = (100 - 0) = 100
Q3 = 200 * 4.19 * 100 = 83800 J
Q4: heat required to boil water to steam
Q = m · ΔHv
Hv = heat of vaporization of water = 2257 J/g
Q4 = 200 * 2257 = 451400 J
Total Q = Q1 + Q2 + Q3 + Q4
Q = 9064 + 66800 + 83800 + 451400
Q = 611,064 Joules
Q = 611.064 kJ
The velocity is 1100 kilometers per hour
Answer:
c
Explanation:
double alit experiment is for wave theory for light
