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3 years ago

1a) An object is thrown up with a velocity of 18m/s from a height of 520m.

Physics

1 answer:

xeze [42]3 years ago

3 0

Answer:

Explanation:

An object is thrown up from a height of 520m

h_o = 520m

Initial velocity of thrown is 18m/s

u = 18m/s

What is the position of the object after 3seconds

t = 3s

Acceleration due to gravity

g = 9.81 m/s²

Let calculated the height the object will reached when thrown from the top.

Using equation of motion

h = ut + ½gt²

Since the body is thrown upward, it is acting against gravity then, gravity will be negative

Then,

h = ut — ½gt²

h = 18 × 3 — ½ × 9.81 × 3²

h = 54 — 44.145

h = 9.855 m

So, the body is above the top of the building at a distance of 9.855m

So, the total distance from the bottom is

Position = h + h_o

x = 9.855 + 520

x = 529.855m

x ≈ 530m,

The position of objects after 3seconds is 520m

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Work needed: 720 J

Explanation:

The work needed to stretch a spring is equal to the elastic potential energy stored in the spring when it is stretched, which is given by

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In this problem, we have

E = 90 J (work done to stretch the spring)

x = 0.2 m (stretching)

Therefore, the spring constant is

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Now we can find what is the work done to stretch the spring by an additional 0.4 m, that means to a total displacement of

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3 years ago

What is the source of all mechanical waves?

frutty [35]

Answer:

The correct answer is A. Vibration.

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gulaghasi [49]

Answer:

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A student at another university repeats the experiment you did in lab. Her target ball is 0.860 m above the floor when it is in

dexar [7]

Answer:

K = 0.076 J

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