Do some research, and look up the difference between the zinc-carbon battery described in the lesson, and the alkaline battery (
shown at the bottom), which is another common dry cell that we use every day. What are the electrodes made of in the alkaline battery? The electrolyte? Does one type have an advantage over the other? Write a short essay.
1 answer:
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Answer:
3.06m/s² to the east
Explanation:
Given parameters:
Mass of car = 2.5 x 10³kg
Force acting on the car = 7.65 x 10³N
Unknown:
Acceleration of the car = ?
Solution:
From Newton's second law of motion:
Force = mass x acceleration
Acceleration = =
= 3.06m/s² to the east
Answer:
a) 6 times farther. b) 6 times longer.
Explanation:
Once released, in the horizontal direction, no other forces act on the ball, so it continues moving at the same initial velocity, which is given by the projection of the velocity vector in the horizontal direction, as follows:
vₓ = v* cos (25º) = 23 m/s * 0.906 = 20.8 m/s
In the vertical direction, the initial velocity is the projection of the velocity vector along the vertical axis, as follows:
vy = v* sin (25º) = 23 m/s * 0.422 = 9.72 m/s
Assuming that the acceleration is constant, and equal to 1/6*g, we can calculate the total time of flight, with the following kinematic equation for the vertical displacement:
If the total displacement in the vertical direction is 0 (which means that the time if the total time of flight), we can solve for t, as follows:
On earth, this time could be calculated in the same way:
As the time is defined by the vertical movement, we can find the horizontal distance travelled on the moon, as follows:
Δx = v₀ₓ * t = 20.8 m/s * 11. 9 s = 248.1 m
On earth, the distance travelled had been as follows:
Δx = v₀ₓ * t = 20.8 m/s * 1.98 s = 41.3 m
⇒ Δx(moon) / Δx(earth) = 248.1 / 41.3 = 6.00
b) As we have just found, the time of flight on the moon and on the earth are as follows:
tmoon = 11. 9 s
tearth = 1.98 s
⇒ t(moon) / t(earth) = 11.9 / 1.98 = 6.0
Answer:
The particle in the D ring is 1399 times faster than the particle in the Encke Division.
Explanation:
The circular velocity is define as:
Where r is the radius of the trajectory and T is the orbital period
To determine the circular velocity of both particles it is necessary to know the orbital period of each one. That can be done by means of the Kepler’s third law:
Where T is orbital period and r is the radius of the trajectory.
Case for the particle in the Encke Division:
It is necessary to pass from kilometers to astronomical unit (AU), where 1 AU is equivalent to 150.000.000 Km ( )
1 AU is defined as the distance between the earth and the sun.
But 1 year is equivalent to 1 AU according with Kepler’s third law, since 1 year is the orbital period of the earth.
That can be expressed in units of days
<em>Circular velocity for the particle in the </em><em>Encke Division</em><em>:</em>
For a better representation of the velocity, kilometers and days are changed to meters and seconds respectively.
⇒ 10247040 s
⇒ 133370000 m
Case for the particle in the D Ring:
For the case of the particle in the D Ring, the same approach used above can be followed
<em>Circular velocity for the particle in </em><em>D Ring</em><em>:</em>
For a better representation of the velocity, kilometers and days are changed to meters and seconds respectively.
⇒ 3786912 s
⇒ 69000000 m
The particle in the D ring is 1399 times faster than the particle in the Encke Division.