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mihalych1998 [28]
3 years ago
15

How many protons does an atom of gold have?

Chemistry
1 answer:
klasskru [66]3 years ago
3 0

Answer:

There are 79 protons in the nucleus of one Gold atom.

Explanation:

The number of protons of any given atom/element can be determined by the atomic number of the specific element, which is found on the periodic table.

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Convert each quantity to the indicated units. a. 3.01g to cg. b. 6200m to km
miss Akunina [59]

a. 301 cg

b. 6.2 km

Explanation:

a. knowing that 1 gram (g) is equal to 100 centigrams (cg) we devise the following reasoning:

if        1 g is equal to 100 cg

then  3.01 g are equal to X cg

X = (3.01 × 100) / 1 = 301 cg

b. knowing that 1 kilometer (km) is equal to 1000 meters (m) we devise the following reasoning:

if         1 km is equal to 1000 m

then   Y km are equal to 6200 m

Y = (6200 × 1) / 1000 = 6.2 km

Learn more about:

converting units of measurement

brainly.com/question/11300981

#learnwithBrainly

5 0
3 years ago
A 5.00-cm cube of magnesium has a mass of 217.501 g. What is the density of magnesiummetal?
Doss [256]

Answer:

d = 43.5 g/cm³

Explanation:

Given data:

Mass of magnesium cube = 217.501 g

Volume of magnesium cube = 5.00 cm³

Density of magnesium cube = ?

Solution:

Formula:

d = m/v

d = density

m = mass

v = volume

by putting values,

d = 217.501 g/ 5.00 cm³

d = 43.5 g/cm³

8 0
3 years ago
What is used to measure heat?
castortr0y [4]

Answer:

O constant specific heat

Explanation:

3 0
3 years ago
These celestial bodies are thought to originate from two different sources. Some are called long-period and originate from the O
Alexus [3.1K]
It’s c I believe because it says 209 years to complete an orbit so hint yourself ?.....
6 0
3 years ago
Read 2 more answers
23) What is the volume of 2.454 x 1024 atoms of nitrogen gas at STP?
earnstyle [38]

Answer:

d) V =  91.3 L

Explanation:

Given data:

Volume of nitrogen = ?

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Number of atoms of nitrogen = 2.454×10²⁴ atoms

Solution:

First of all we will calculate the number of moles of nitrogen by using Avogadro number.

1 mole = 6.022×10²³ atoms

2.454×10²⁴ atoms × 1 mol / 6.022×10²³ atoms

0.407×10¹ mol

4.07 mol

Volume of nitrogen:

PV = nRT

1 atm × V = 4.07 mol ×0.0821 atm.L /mol.K ×273.15 K

V =  91.3 atm.L /1 atm

V =  91.3 L

3 0
3 years ago
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