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sukhopar [10]
3 years ago
12

A 3.20-mol sample of gas occupies a volume of 350. mL at 300.0 K. Determine the

Chemistry
1 answer:
nalin [4]3 years ago
4 0

Answer:

P \approx 225atm

Explanation:

From the question we are told that:

Moles of sample n=3.20_mol

Volume V=350mL

Temperature T=300k

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 P=\frac{nRT}{V}

 P=\frac{3.20*0.08206*300}{350*10^{-3}}

 P=225.079atm

 P \approx 225atm

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What percentage of the mass of 1 mole of CH3Cl is derived from carbon?​
steposvetlana [31]

Answer:

Element Symbol Atomic weight Atoms Mass percent

Carbon C                  12.0107               1              23.7894

Hydrogen H         1.00794                3         5.9892

Chlorine Cl                 35.453                 1       70.2213

Explanation:

3 0
3 years ago
(7) need help asappp plss
natima [27]

Answer:

See explanation

Explanation:

The cold drink chiller is a cold substance which is inserted into a bottle of drink which contains warm liquid particles at a particular temperature.

Once the drink chiller is inserted, the liquid molecules around the drink chiller become cooler, denser and sink away from the drink chiller. Other warmer, less dense molecules of the liquid drink now replaces them around the drink chiller.

A convection current is thus set up for as long as the drink chiller is working.

3 0
3 years ago
What volume would a sample of gas occupy in LITERS at 0.985 atmospheres and a volume of 3.65 liters if the pressure were raised
musickatia [10]

Answer:

3.18 L

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 0.985 atm
  • Initial volume (V₁): 3.65 L
  • Final pressure (P₂): 861.0 mmHg
  • Final volume (V₂): ?

Step 2: Convert P₁ to mmHg

We will use the conversion factor 1 atm = 760 mmHg.

0.985 atm × 760 mmHg/1 atm = 749 mmHg

Step 3: Calculate the final volume of the gas

Assuming ideal behavior and constant temperature, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 749 mmHg × 3.65 L/861.0 mmHg = 3.18 L

7 0
3 years ago
Which of the following represents six molecules of water? 6HO 2 6H 2O 1 6H 2O H 6O
n200080 [17]

Answer:

6H20 represents six molecules of water

8 0
3 years ago
Read 2 more answers
You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

3 0
3 years ago
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