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sukhopar [10]
3 years ago
12

A 3.20-mol sample of gas occupies a volume of 350. mL at 300.0 K. Determine the

Chemistry
1 answer:
nalin [4]3 years ago
4 0

Answer:

P \approx 225atm

Explanation:

From the question we are told that:

Moles of sample n=3.20_mol

Volume V=350mL

Temperature T=300k

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 P=\frac{nRT}{V}

 P=\frac{3.20*0.08206*300}{350*10^{-3}}

 P=225.079atm

 P \approx 225atm

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37.8g/ 10.81g/mol = 3.4968...moles

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What causes the earth’s magnetic field? A. currents in the earth’s liquid-metal outer core B. the mineral composition of the ear
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A. Which line represents travel at the fastest speed? Justify your answer.__
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Which line represents travel at the fastest speed? Justify your answer.__

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b. Describe the line that should be added for an object that is not moving with respect to the chosen reference point.__

Answer the question using 5 complete sentences and the vocabulary terms; velocity, position, and distance

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3 years ago
What happens when the concentration of water inside a cell is lower than the concentration of water outside the cell?
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Answer:

Water outside the cell will flow inwards by osmosis to attain equilibrium

Explanation:

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If concentrations of dissolved solutes are greater inside the cell, the concentration of water inside the cell is correspondingly lower. As a result, water outside the cell will flow inwards by osmosis to attain equilibrium.

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3 years ago
A 1.0-L buffer solution is 0.10 M in HF and 0.050 M in NaF. Which action destroys the buffer? (a) adding 0.050 mol of HCl (b) ad
Volgvan

Answer:

(a) adding 0.050 mol of HCl

Explanation:

A buffer is defined as the mixture of a weak acid and its conjugate base -or vice versa-.

In the buffer:

1.0L × (0.10 mol / L) = 0.10 moles of HF -<em>Weak acid-</em>

1.0L × (0.050 mol / L) = 0.050 moles of NaF -<em>Conjugate base-</em>

-The weak acid reacts with bases as NaOH and the conjugate base reacts with acids as HCl-

Thus:

<em>(a) adding 0.050 mol of HCl:</em> The addition of 0.050moles of HCl produce the reaction of 0.050 moles of NaF producing HF. That means after the reaction, all NaF is consumed and you will have in solution just the weak acid <em>destroying the buffer</em>.

(b) adding 0.050 mol of NaOH: The NaOH reacts with HF producing more NaF. Would be consumed just 0.050 moles of HF -remaining 0.050 moles of HF-. Thus, the buffer <em>wouldn't be destroyed</em>.

(c) adding 0.050 mol of NaF: The addition of conjugate base <em>doesn't destroy the buffer</em>

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