Answer:
3 atoms of O
8.57g
Explanation:
The problem here is to find the mass of oxygen in the compound and the number of atoms of oxygen.
The formula of the compound is:
NaHCO₃;
Here we have:
1 atom of Na
1 atom of H
1 atom of C
3 atoms of O
So there are 3 atoms of O
To find the mass of oxygen , we use the molar mass of oxygen;
Molar mass of oxygen = 16g/mol
Mass of oxygen =
x 15 = 8.57g
The mass of magnesium in
atoms is 240 g.
Answer: Option A
<u>Explanation:</u>
First, we have to convert the atoms to moles of magnesium.
We know that
atoms are present in 1 mole of magnesium. So,


Thus,


Thus, 240 g of Magnesium is present in
atoms.
An energy level of a certain atom is further divided into the orbitals. There are four (4) orbitals. These are the s orbitals, p orbitals, d orbitals, and f orbitals. They are already arranged above as to how they are to be filled. The number of electrons that each can hold are as follows:
s orbitals = 2 electrons
p orbitals = 6 electrons
d orbitals = 10 electrons
f orbitals = 14 electrons
<h3><u> Answer</u>;</h3>
= 4.0 L
<h3><u>Explanation;</u></h3>
Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to pressure at a constant temperature.
Therefore; <em>Volume α 1/pressure</em>
<em>Mathematically; V α 1/P</em>
<em>V = kP, where k is a constant;</em>
<em>P1V1 = P2V2</em>
<em>V1 = 0.5 l, P1 =203 kPa, P2 = 25.4 kPa</em>
<em>V2 = (0.5 × 203 )/25.4 </em>
<em> = 3.996 </em>
<em> ≈ </em><em><u>4.0 L</u></em>