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erik [133]
3 years ago
5

Which element is considered to be a transition element? F Sn Cu Na

Chemistry
1 answer:
solmaris [256]3 years ago
7 0

Answer:

Im pretty sure its F

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Sufficient strong acid is added to a solution containing na2hpo4 to neutralize one-half of it. what will be the ph of this solut
Ivahew [28]
Assuming that the initial pH is pHi.
The initial concentration of [OH-] is
[OH]- = 10^(14 - pHi)

Since half of the Na2HPO4 is neutralized, the concentration of [OH-] will be reduced to half. The new pH will be
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The Atlantic ocean grows in size due to a<br> Divergent boundaries
KIM [24]

Answer:

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Explanation:

7 0
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The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wave
timofeeve [1]

Explanation:

It is given that,

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

n_i=8

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The amount of energy change during the transition is given by :

\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

And

\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

Plugging all the values we get :

\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5

So, the final level of the electron is 5.

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The sun provides energy through nuclear fusion by fusing the atoms of hydrogen and helium in the suns core, so the answer is D
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3 years ago
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describe covalent and ionic bonding. include how it works, any key terms and how you can identify each bond ( hard, soft, rigid,
Katena32 [7]
A covalent bond is a bond between 2 non metals, they share electrons. Ionic bonding occurs between a metal and a non-metal, and they transfer electrons. 
5 0
3 years ago
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