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Olin [163]
3 years ago
5

A small box measures 7 in. by 10 in. by 3/4 in. high. Find the volume of the box.

Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

Volume = 52.5

Step-by-step explanation:

volume of a rectangular 3d shape can be calculated by length*width*height. In this case:

7*10*0.75 = 52.5

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What is the value of -5 to the 4th power? <br><br> A) 20<br> B) 625<br> C) 125<br> D) -625
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Answer:

B) 625

Step-by-step explanation:

(-5)^4

-5*-5*-5*-5

25*25

625

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For her phone service, Melissa pays a monthly fee of $16, and she pays an additional $0.06 per minute of use. The least she has
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Step-by-step explanation:

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3 years ago
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What are the restrictions for a? 2a^2+a-15/5a^2+16a+3
koban [17]

ANSWER


The restrictions are

a\ne -3,a\ne -\frac{1}{5}


EXPLANATION


We were given the rational function,


\frac{2a^2+a-15}{5a^2+16a+3}


The function is defined for all values of a, except



5a^2+16a+3=0


This has become a quadratic trinomial, so we need to split the middle term.


We do that by multiplying the coefficient of x^2 which is 5 by the constant term which is 3. This gives us 15.


The factors of 15 that adds up to 16 are 1 and 15.


We use these factors to split the middle term.




5a^2+15a+a+3=0


We now factor to get,


5a(a+3)+1(a+3)=0


We factor further to get,


(a+3)(5a+1)=0



This implies that,


(a+3)=0,(5a+1)=0


This gives


a=-3,a=-\frac{1}{5}


These are the restrictions.





8 0
3 years ago
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