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Furkat [3]
3 years ago
9

In a scatterplot how do you tell if there's a correlation between production cost and gross income

Mathematics
1 answer:
Ymorist [56]3 years ago
4 0
If the x axis increases as the y axis increases then it's a positive correlation
and if the x axis decreases and the y axis increases or the other way round then it is negative correlation
and if there is no clear pattern it has no correlation
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A tank contains 10 liters of pure water. Saline solution with a variable concentration 5 grams of salt per liter is pumped into
algol [13]

Answer:

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

Step-by-step explanation:

The mass flow rate dQ(t)/dt = mass flowing in - mass flowing out

Since 5 g/L of salt is pumped in at a rate of 4 L/min, the mass flow in is thus 5 g/L × 4 L/min = 20 g/min.

Let Q(t) be the mass present at any time, t. The concentration at any time ,t is thus Q(t)/volume = Q(t)/10. Since water drains at a rate of 4 L/min, the mass flow out is thus, Q(t)/10 g/L × 4 L/min = 2Q(t)/5 g/min.

So, dQ(t)/dt = mass flowing in - mass flowing out

dQ(t)/dt = 20 g/min - 2Q(t)/5 g/min

Since the salt just begins to be pumped in, the initial mass of salt in the tank is zero. So Q(0) = 0

So, the initial value problem is thus

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

3 0
2 years ago
Could someone please solve this and explain how to do it?
galben [10]

Answer:

no clue buddy sry

Step-by-step explanation:

4 0
3 years ago
1/4 + 7/16 =??<br> Help me please
Sholpan [36]

Answer:

4+7/16

Answer is 11/16

Step-by-step explanation:

Transform the expression then calculate

5 0
3 years ago
Read 2 more answers
Two equal angles of an isosceles triangle are called
Leviafan [203]

legs

hope this helps you


3 0
3 years ago
Complete the identity, sin(a+b)/cosacosb=​
8090 [49]

Answer:

tana + tanb

Step-by-step explanation:

Using the trigonometric identities

• sin(a + b) = sinacosb + cosasinb

• tanx = \frac{sinx}{cosx}, then

\frac{sin(a+b)}{cosacosb}

= \frac{sinacosb+cosasinb}{cosacosb}

= \frac{sinacosb}{cosacosb} + \frac{cosasinb}{cosacosb}

= \frac{sina}{cosa} + \frac{sinb}{cosb}

= tana + tanb

5 0
3 years ago
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