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elena-14-01-66 [18.8K]

3 years ago

11

Answers?

2 answers:

MakcuM [25]3 years ago

5 0

Answer:

The sum of 68 and 14 = 82

The product of 56 and 65 = 3640

The difference between 78 and 24 = 54

The quotient of 648 and 13 = 49.84

65 multiplied by 45 = 2925

Find the quotient of 230 and 5, then add 47 = 93

Subtract 43 and 12, then divide by 3 = 10.33

Find the product of 681 and 23, then subtract by 4 = 15659

Add 9 to the difference of 19 and 8 = 20

Multiply the sum of 87 and 16 by 13 = 1339

Subtract 56 from the product of 58 and 42 = 2380

Add 99 to the quotient of 850 and 10 = 184

marshall27 [118]3 years ago

3 0

Answer:

I'll put it in the explaining portion.

Step-by-step explanation:

The sum of 68 and 14 = 82

The product of 56 and 65 = 3640

The difference between 78 and 24 = 54

The quotient of 648 and 13 = 49.8461538462

65 multiplied by 45 = 2925

Find the quotient of 230 and 5, then add 47 = 93

Subtract 43 and 12, then divide by 3 = 10.333333333....

Find the product of 681 and 23, then subtract by 4 = 15659

Add 9 to the difference of 19 and 8 = 20

Multiply the sum of 87 and 16 by 13 = 1339

Subtract 56 from the product of 58 and 42 = 2380

Add 99 to the quotient of 850 and 10 = 184

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Simplify #53: 3(x + 2) - 4x<br><br><br><br> Help please

labwork [276]

Answer:

-x+6

Step-by-step explanation:

3(x+2)-4x

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2 years ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$

Substitute point (1, -1) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}$

Equate to find h:

$\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}$

Substitute found value of h into one of the equations to find a:

$\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}$

Substitute found values of h and a to find k:

$\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}$

Therefore, the equation of the parabola in vertex form is:

$\implies y=3(x-0)^2-4=3x^2-4$

So the vertex of the parabola is (0, -4)

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Step-by-step explanation:

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Step-by-step explanation:

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