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elena-14-01-66 [18.8K]

3 years ago

11

Answers?

2 answers:

MakcuM [25]3 years ago

5 0

Answer:

The sum of 68 and 14 = 82

The product of 56 and 65 = 3640

The difference between 78 and 24 = 54

The quotient of 648 and 13 = 49.84

65 multiplied by 45 = 2925

Find the quotient of 230 and 5, then add 47 = 93

Subtract 43 and 12, then divide by 3 = 10.33

Find the product of 681 and 23, then subtract by 4 = 15659

Add 9 to the difference of 19 and 8 = 20

Multiply the sum of 87 and 16 by 13 = 1339

Subtract 56 from the product of 58 and 42 = 2380

Add 99 to the quotient of 850 and 10 = 184

marshall27 [118]3 years ago

3 0

Answer:

I'll put it in the explaining portion.

Step-by-step explanation:

The sum of 68 and 14 = 82

The product of 56 and 65 = 3640

The difference between 78 and 24 = 54

The quotient of 648 and 13 = 49.8461538462

65 multiplied by 45 = 2925

Find the quotient of 230 and 5, then add 47 = 93

Subtract 43 and 12, then divide by 3 = 10.333333333....

Find the product of 681 and 23, then subtract by 4 = 15659

Add 9 to the difference of 19 and 8 = 20

Multiply the sum of 87 and 16 by 13 = 1339

Subtract 56 from the product of 58 and 42 = 2380

Add 99 to the quotient of 850 and 10 = 184

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geniusboy [140]

Answer:

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

The answer of the above definite integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

Step-by-step explanation:

The given limit interval is

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The corresponding definite integral may be written as

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Bonus:

The definite integral may be solved as

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98$

Therefore, the answer to the integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

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