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MrRa [10]
2 years ago
11

A plant costs p dollars and a bush costs b dollars. Ana buys 2 plants and 4 bushes for $42. Paola buys 7 plants and 9 bushes for

$107. Write down a pair of simultaneous equations and solve them to find out the value of p and the value of b.
Mathematics
2 answers:
gregori [183]2 years ago
4 0

Answer:

p = 5 and b = 8

Step-by-step explanation:

First, create a system of equations:

2p + 4b = 42

7p + 9b = 107

Solve by elimination by multiplying the top equation by -7 and the bottom equation by 2:

-14p - 28b = -294

14p + 18b = 214

Add these together, and solve for b:

-10b = -80

b = 8

Plug in 8 as b into one of the equations, and solve for p:

2p + 4b = 42

2p + 4(8) = 42

2p + 32 = 42

2p = 10

p = 5

So, p = 5 and b = 8

fredd [130]2 years ago
4 0

Answer:

p = 5 and b =8

Step-by-step explanation:

2p + 4b = 42

2p = 42 - 4b

p = 21 - 2b

7p + 9b = 107

7 (21 - 2b) + 9b = 107

147 - 14b + 9b = 107

147 - 5b = 107

-5b = -40

b = 8

2p + 4 * 8 = 42

2p + 32 = 42

2p = 10

p = 5

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Explanation:

You first minus 5 to the other side which gave you -3 . Then you minus the 5x to the other side which gave you -1. After than just need to divide -1 to both side, switch the > and you’ll get the answer! Hope the explanation makes sense.
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50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Nataliya [291]
<h3>Answer:   9</h3>

========================================================

Work Shown:

Apply the pythagorean theorem

a^2 + b^2 = c^2

12^2 + b^2 = 15^2

144 + b^2 = 225

b^2 = 225-144

b^2 = 81

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The mean annual cost of an automotive insurance policy is normally distributed with a mean of $1140 and standard deviation of $3
DerKrebs [107]

Using the normal distribution, it is found that the probabilities are given as follows:

a) 0.8871 = 88.71%.

b) 0.0778 = 7.78%.

c) 0.8485 = 84.85%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

The parameters in this problem are given as follows:

\mu = 1140, \sigma = 310, n = 16, s = \frac{310}{\sqrt{16}} = 77.5

Item a:

The probability is the <u>p-value of Z when X = 1250 subtracted by the p-value of Z when X = 1000</u>, hence:

X = 1250:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1250 - 1140}{77.5}

Z = 1.42

Z = 1.42 has a p-value of 0.9222.

X = 1000:

Z = \frac{X - \mu}{s}

Z = \frac{1000 - 1140}{77.5}

Z = -1.81

Z = -1.81 has a p-value of 0.0351.

0.9222 - 0.0351 = 0.8871 = 88.71% probability.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 1250</u>, hence:

1 - 0.9222 = 0.0778 = 7.78%.

Item c:

The probability is the <u>p-value of Z when X = 1220</u>, hence:

Z = \frac{X - \mu}{s}

Z = \frac{1220 - 1140}{77.5}

Z = 1.03

Z = 1.03 has a p-value of 0.8485.

0.8485 = 84.85% probability.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

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