By sine law
sin45/16.5= sinB'/22
sinB'= sqrt2/2/16.5*22=
B'= 70.5
B=180-70.5=109.5
Answer:
The value of pressure at an altitude of 10000 ft = 10 
Step-by-step explanation:
Given data
Atmospheric pressure
= 14.7 
Pressure at 4000 ft = 12.6 
If temperature is constant then the atmospheric pressure is varies with the altitude according to law
P (h) =
------ (1)
where k= constant & h = height
12.6 = 14.7 
0.857 = 
㏑ 0.857 = - 4000 k
-0.154 = - 4000 k
k = 3.85 × 
Thus the atmospheric pressure at an altitude of 10,000 ft is
14.7 ×
----- (2)
Product of k & h is
k h = 3.85 ×
× 10000
k h = 0.385
Put his value of k h = 0.385 in equation (2) we get
14.7 × 
10 
This is the value of pressure at an altitude of 10000 ft.
Answer:
if im correct i think the answer is y=1.25x-0.5
Step-by-step explanation:
Answer:
1 upon 12 i think but not sure
600 becuase 90/.30= 300 and 300*2 =600