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Arte-miy333 [17]
3 years ago
10

A wildlife biologist is doing research on chronic wasting disease and its impact on the deer populations in northern Colorado. T

o estimate the difference between the proportions of deer with chronic wasting disease in two different regions, a random sample of 200 deer was obtained from one region and a random sample of 197 deer was obtained from the other region. The biologist checked for the following.
(200) (0.06) >= 10
(200) (0.94) >=10
(197)(0.086) >=10
(197)(0.914) >= 10

Which of the following conditions for inference was the biologist checking?

a. The population of deer within each region is approximately normal.
b. it is reasonable to generalize from the samples to the populations.
c. The samples are independent of each other.
d. The observations within each sample are close to independent.
e. The sampling distribution of the difference in sample proportions is approximately normal Prisen.
Mathematics
1 answer:
jonny [76]3 years ago
4 0

Answer: The sampling distribution of the difference in sample proportions is approximately normal

Step-by-step explanation:

Given that :

Random sample of deer from one region = 200

p = 0.06

1 - p = 1 - 0.06 = 0.94

Random sample of deer from other region = 197

p = 8.6% = 0.086

1 - p = 1 - 0.086 = 0.914

For an approximately normal distribution :

np ≥ 10

n(1 - p) ≥ 10

(200) (0.06) = 12

(200) (0.94) = 188

(197)(0.086) = 16.942

(197)(0.914) = 180.058

Since all conditions are met :

Then, the sampling distribution of the difference in sample proportion is approximately normal.

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where p0 is the atmospheric pressure at sea level and k is a constant. If the atmospheric pressure is 14.7 lb/in.2 at sea level
balu736 [363]

Answer:

The value of pressure at an altitude of 10000 ft = 10 \frac{lb}{in^{2} }

Step-by-step explanation:

Given data

Atmospheric pressure P_{0} = 14.7 \frac{lb}{in^{2} }

Pressure at 4000 ft = 12.6 \frac{lb}{in^{2} }

If temperature is constant then the atmospheric pressure is varies with the altitude according to law

P (h) = P_{0} e^{- kh} ------ (1)

where k= constant & h = height

12.6 = 14.7 e^{- 4000k}

0.857 = e^{- 4000k}

㏑ 0.857 = - 4000 k

-0.154 = - 4000 k

k = 3.85 × 10^{-5}

Thus the atmospheric pressure at an altitude of 10,000 ft is

P_{10000} = 14.7 × e^{- kh} ----- (2)

Product of k & h is

k h = 3.85 × 10^{-5} × 10000

k h = 0.385

Put his value of k h = 0.385  in equation (2) we get

P_{10000} = 14.7 × e^{-0.385 }

P_{10000} = 10 \frac{lb}{in^{2} }

This is the value of pressure at an altitude of 10000 ft.

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Answer:

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Step-by-step explanation:


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Answer:

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