Answer:
B
Step-by-step explanation:
Brainliest please, thanks :)
The answer to the question that needs to go on the top is 33
Assuming she set up the problem vertically, she began subtracting from the left, instead if the right.
At first, we need to find x.
QR = LN
2x+1 = 3x-7
x=8
Substitute value of a=8 into QR = 2x+1.
QR = 2*8+1 = 17
QR =17
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701