All categories

2 years ago

D. 9x-X+5x =260 Bx= 200

Mathematics

1 answer:

yan [13]2 years ago

8 0

Answer:

We first must solve for x

$9x-x+5x=260\\13x=260\\x=30$

When we have x, we put it in to the second equation

$Bx=200\\\\B=\frac{200}{x} \\\\B=\frac{200}{30}\\\\B=\frac{20}{3}$

You might be interested in

Can anyone help me on #7 and #8

Leno4ka [110]

This is all you have to do.

8 0

3 years ago

Read 2 more answers

What does 6 27/18-3 3/8=

ludmilkaskok [199]

Easy. The answer would be 4 1/8.

3 0

3 years ago

In the trapezoid ABCD (AB∥CD) point M∈AD, so that AM:MD=3:5. Line L ∥AB and going through point M intersects diagonal AC and leg

siniylev [52]

Answer:

$\dfrac{AP}{PC}=\dfrac{3}{5}$

$\dfrac{BN}{CN}=\dfrac{3}{5}$

Step-by-step explanation:

Consider triangles AMP and ADC. In these triangles,

angle A is the common angle, so $\angle MAP\cong \angle DAC$ by reflexive property;
angles AMP and ADC are congruent as corresponding angles when two parallel lines MP and CD are cut by transversal AD.

Hence, triangles AMP and ADC are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

$\dfrac{AM}{AD}=\dfrac{AP}{AC}\\ \\\dfrac{3x}{3x+5x}=\dfrac{AP}{AC}\\ \\\dfrac{AP}{AC}=\dfrac{3}{8}\Rightarrow AP=\dfrac{3}{8}AC\\ \\PC=AC-AP=AC-\dfrac{3}{8}AC=\dfrac{5}{8}AC,$

$\dfrac{AP}{PC}=\dfrac{\frac{3}{8}AC}{\frac{5}{8}AC}=\dfrac{3}{5}$

Consider triangles ACB and PCN. In these triangles,

angle C is the common angle, so $\angle ACB\cong \angle PCN$ by reflexive property;
angles ABC and PCN are congruent as corresponding angles when two parallel lines PN and AB are cut by transversal BC.

Hence, triangles ACB and PCN are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

$\dfrac{CP}{AP}=\dfrac{CN}{CB}\\ \\\dfrac{5x}{3x+5x}=\dfrac{CN}{CB}\\ \\\dfrac{CN}{CB}=\dfrac{5}{8}\Rightarrow CN=\dfrac{5}{8}CB\\ \\BN=BC-CN=BC-\dfrac{5}{8}BC=\dfrac{3}{8}BC,$

$\dfrac{BN}{CN}=\dfrac{\frac{3}{8}BC}{\frac{5}{8}BC}=\dfrac{3}{5}$

4 0

3 years ago

a conference session is 30 minutes long Thursday 614 students participate what is the total number of minutes

horrorfan [7]

614 because if you take the number of students and divide that by the medita session is you get 20.46666 and on and then you multiply that by 30 minute long is that his car and you get the number you started with.

8 0

3 years ago

A volleyball coach plans her daily practices to include 10 minutes of stretching, 2/3 of the entire practice scrimmaging, and th

ASHA 777 [7]

Since it is 100 minutes of stretching and scrimmaging, we can subtract the 10 minutes we know is stretching. 90 minutes is equal to 2/3 of the practice then. Divide by 2 and multiply by 3 to get the entire time of the practice or 135 minutes. However, you asked for it in hours, so we can subtract 120 minutes because this is 2 hours. 15 minutes is 1/4 of an hour. So practice took 2&1/4 hours. Hope that helps.

5 0

3 years ago

Read 2 more answers