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Luda [366]
3 years ago
15

Find the average rate of change of f(x) = x^2–5x+1 from x = 2 to x= 5.

Mathematics
1 answer:
Agata [3.3K]3 years ago
3 0

Answer:

12

Step-by-step explanation:

it should be the answer if not messge me so we can work it out

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Giving brainliest!! easy*
DaniilM [7]

Answer:

1584mm^2

Step-by-step explanation:

20 x20 = 400 and there are 3 of them

400+400+400 = 1200

1/2(16x24 ) =192 and there are 2 of them

192+192 = 384

1200+384

8 0
3 years ago
Read 2 more answers
PLZ HELP AND EXPLAIN !! Arron borrowed $200 from his cousin. He promised to repay the loan in 2 years at a simple annual interes
Dmitriy789 [7]
The first thing you have to do is know the equation. The equation is a(1+p)^t.
a= the amount of money p= the percent represented as a decimal and t=time ( the t is raised as an exponent)
so, in this case, it is represented as 200(1+0.05)^2\
200(1.05)^2
200(1.1025)
220.5 That is how much extra he would owe in interest fee's

5 0
3 years ago
Me.Pete is building a rectangular fence around his house.The fence will be 32 feet long and 29 feet wide.What will be the perime
Bad White [126]

Answer:

122

Step-by-step explanation:

32+32+29+29=122

3 0
3 years ago
Draw a factor tree the prime factorization of 45 and 90 in the space provided below
Ann [662]
45                                        90 
 /  \                                       /  \
5  9                                     45  2
   /  \                                   /  \
  3   3                                5   9 
 5x3x3                                   / \  
                                          3    3
                                        2x5x3x3
3 0
3 years ago
Matching Functions
Ainat [17]

Answer:

Graph A → Equation A → Table B → Property D

Graph D → Equation B → Table A → Property B

Graph B → Equation C → Table C → Property E

Graph C → Equation D → Table E → Property A

Graph E → Equation E → Table D → Property C

Step-by-step explanation:

Graph A corresponds to equation A, x·y = 2, and Table B → Property D

xy = 2 has a vertical asymptote at x = 0, and a horizontal asymptote at y = 0

y = 2/x, when x = 0, y = ∞

Graph D corresponds to equation B, -\left |  x\right | + 1 which corresponds to table A → Property B

The domain extends from (-∞, ∞), and [1, -∞)

Graph B corresponds to equation C, -(x + 2)² which gives the values in Table C and Property E wich is a horizontal shift of 2 units left and a reflection across the x-axis

Graph C corresponds to equation D, (1/3)·x - 2, which gives the values on Table E and Property A

The y-intercept of (1/3)·x - 2 = (0, -2), and the x-intercept = (6, 0)

Graph E corresponds to equation E, x³ = y, which gives the values on Table D  Property C, y is x cubed

6 0
3 years ago
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